查找包含数组中子字符串的字符串的索引

Question

我试图找到包含数组中子字符串的字符串元素的索引。我尝试了Array#indexOf，但它总是返回-1。

我做错了什么？

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var array = ["OTHER-REQUEST-DEPT1", "OTHER-REQUEST-DEPT2", "OTHER-REQUEST-DEPT3"]
var string = "DEPT2"
console.log(array.indexOf(string));

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Answer 1

SELECT . . . FROM ptsweb.tblCustomerInqry i LEFT OUTER JOIN ptsweb.tblCustomer tc ON tc.CustomerID = i.CustomerID OUTER APPLY (SELECT TOP (1) p.* FROM ptsweb.tblProposal p WHERE tc.CustomerID = p.CustomerID ORDER BY p.DateCreated DESC ) p WHERE i.CustInqDate > '2017-01-01' AND tc.CustomerID = 101568; 找到等于其参数的数组项的索引。

您没有等于 Array.indexOf()的任何数组元素。

听起来你想要检查数组是否包含（或找到索引）包含字符串的任何元素，使用带有箭头的"DEPT2"或.some()调用.findIndex()。

的函数

Answer 2

扩展SLaks的答案，下面是一些功能实例，根据包含数组子字符串的字符串的位置实现不同的结果。

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const array = ["OTHER-REQUEST-DEPT1","OTHER-REQUEST-DEPT2","OTHER-REQUEST-DEPT3"];
const string = "DEPT2";

console.log(array.find     (e => e.includes(string)));
console.log(array.findIndex(e => e.includes(string)));
console.log(array.some     (e => e.includes(string)));
console.log(array.reduce   ((m, e, i) => e.includes(string) ? Object.assign(m, { [i]: e }) : m, {}));
console.log(array.filter   (e => e.includes(string)));

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