我正在尝试开始使用Rust,并尝试将一些部分组合在一起,然后设置一个" Server"包含Vector"客户"的实例其中每个人都有一个插座。
据我所知,在Rust中,Socket或TcpStream需要是可变的,并且我需要借用引用以便在主循环中的Client实例化之后保留范围。
但我遇到的问题是我的TcpStream字段在Client结构中可能不可变。所以我不确定我的方法是否正确,但我尝试使用生命周期参数<' a>来解决这个问题,但是这导致了另一个我的"客户端"内部"服务器"没有通过<&a;>终身参数。
有人可以帮我解决这个问题或向我展示解决这个问题/解决方案的正确方法吗?
感谢。
use std::net::*;
use std::io::Write;
use std::thread;
use std::time::Duration;
struct Client<'a> {
socket: &'a mut TcpStream,
addr: SocketAddr
}
struct Server {
clients: Vec<Box<Client>>
}
impl Server {
pub fn new() -> Server {
Server{clients: Vec::new()}
}
fn write(&self, stream: &mut TcpStream) {
let mut counter: u32 = 0;
counter += 1;
stream.write(counter.to_string().as_bytes()).unwrap();
thread::sleep(Duration::from_secs(1));
}
fn client_thread(&self, client: &mut Client) {
self.write(&mut client.socket);
}
fn add_client(&self, socket: &mut TcpStream, addr: SocketAddr) {
let mut client = Client {
socket: socket,
addr: addr
};
self.clients.push(Box::new(client));
self.client_thread(&mut client);
}
pub fn server_loop(&self) {
let listener = TcpListener::bind("127.0.0.1:5001").unwrap();
loop {
match listener.accept() {
Ok((mut socket, addr)) => {
println!("new client: {:?}", addr);
thread::spawn(move || loop {
self.add_client(&mut socket, addr);
});
},
Err(e) => println!("couldn't get client: {:?}", e),
}
}
}
}
fn main() {
let mut server = Server::new();
server.server_loop();
}
更新
当前的错误消息是:
clients: Vec<Box<Client>>
^^^^^^ expected lifetime parameter
更新2:
现在我认为解决方案更接近目标了。但我仍然遇到线程问题:在静态上下文之外生成。
use std::net::*;
use std::io::Write;
use std::thread;
struct Client {
socket: TcpStream
}
struct Server {
clients: Vec<Box<Client>>
}
impl Server {
fn new() -> Server {
Server{clients: vec![]}
}
fn write(&mut self, stream: &mut TcpStream) {
let mut counter: u32 = 0;
stream.write(counter.to_string().as_bytes()).unwrap();
}
fn client_loop(&mut self, client: &mut Client) {
loop {
self.write(&mut client.socket);
}
}
fn add_client(&mut self, s: TcpStream) {
let mut client = Client{
socket: s
};
self.clients.push(Box::new(client));
println!("New client: {}", client.socket.peer_addr().unwrap());
thread::spawn(move || {
self.client_loop(&mut client);
});
}
pub fn server_loop(&mut self) {
let listener = TcpListener::bind("127.0.0.1:5001").unwrap();
loop {
match listener.accept() {
Ok((socket, _addr)) => {
self.add_client(socket);
},
Err(e) => println!("Couldn't get client: {}", e),
}
}
}
}
fn main() {
let mut server = Server::new();
server.server_loop();
}
错误[E0477]:类型[closure@src/main.rs:38:23: 40:10 self:&mut Server, client:Client]
无法满足所需的生命周期
--> src/main.rs:38:9
|
38 | thread::spawn(move || {
| ^^^^^^^^^^^^^
|
= note: type must satisfy the static lifetime
答案 0 :(得分:0)
我现在能够解决整体问题:
use std::net::*;
use std::io::Write;
use std::thread;
struct Client {
socket: TcpStream,
}
impl Client {
pub fn write(&mut self) {
let counter: u32 = 0;
self.socket.write(counter.to_string().as_bytes()).unwrap();
}
}
struct ClientThread {
inner: Client,
}
impl ClientThread {
pub fn client_loop(&mut self) {
let client = &mut self.inner;
client.write();
}
}
struct Server {
_clients: Vec<Box<Client>>,
}
impl Server {
fn new() -> Server {
Server { _clients: vec![] }
}
fn add_client(&mut self, s: TcpStream) {
let client = Client { socket: s };
println!("New client: {}", client.socket.peer_addr().unwrap());
self._clients.push(Box::new(client));
let mut client_thread = ClientThread { inner: client };
thread::spawn(move || loop {
client_thread.client_loop();
});
}
pub fn server_loop(&mut self) {
let listener = TcpListener::bind("127.0.0.1:5001").unwrap();
loop {
match listener.accept() {
Ok((socket, _addr)) => {
self.add_client(socket);
}
Err(e) => println!("Couldn't get client: {}", e),
}
}
}
}
fn main() {
let mut server = Server::new();
server.server_loop();
}