所以我想列出相册,其中每张专辑都包含单张照片。这类似于每个类别都有帖子的类别。 我有两个数据库表,即"专辑"和"照片"。 相册表包含列id,album_name和album_description。 照片表包含列ID,photo_is_in,photo_name和photo_description。
我使用INNER JOIN来合并相册和照片表,以生成下面的平面$ albums数组:
<?php
$albums = [
['album_id' => '1', 'photo_id' => '41', 'album_name' => 'album_1', 'album_description' => 'Album 1 description', 'photo_is_in' => 'album_1', 'photo_name' => 'photo_1.jpg', 'photo_description' => 'Photo 1 description'],
['album_id' => '1', 'photo_id' => '42', 'album_name' => 'album_1', 'album_description' => 'Album 1 description', 'photo_is_in' => 'album_1', 'photo_name' => 'photo_2.jpg', 'photo_description' => 'Photo 2 description'],
//==================
['album_id' => '2', 'photo_id' => '43', 'album_name' => 'album_2', 'album_description' => 'Album 2 description', 'photo_is_in' => 'album_2', 'photo_name' => 'photo_3.jpg', 'photo_description' => 'Photo 3 description'],
['album_id' => '2', 'photo_id' => '44', 'album_name' => 'album_2', 'album_description' => 'Album 2 description', 'photo_is_in' => 'album_2', 'photo_name' => 'photo_4.jpg', 'photo_description' => 'Photo 4 description'],
];
?>
我想将上面的$ albums数组转换为如下所示的分层数组:
<?php
$sameAlbums = Array(
'album_1' => Array( //comes from 'album_name' => 'album_1' in the $data array above
'album_id' => '1',
'album_description' => 'Album 1 description',
'album_1' => Array( //comes from 'photo_is_in' => 'album_1' in the $data array above
'photo_1.jpg' => Array(
'photo_id' => '41',
'photo_description' => 'Photo 1 description',
),
'photo_2.jpg' => Array(
'photo_id' => '42',
'photo_description' => 'Photo 2 description',
)
)
),
//============================================
'album_2' => Array( //comes from 'album_name' => 'album_2' in the $data array above
'album_id' => '2',
'album_description' => 'Album 2 description',
'album_2' => Array( //comes from 'phot_is_in' => 'album_2' in the $data array above
'photo_3.jpg' => Array(
'photo_id' => '43',
'photo_description' => 'Photo 3 deescription',
),
'photo_3.jpg' => Array(
'photo_id' => '44',
'photo_description' => 'Photo 4 deescription',
)
)
)
);
?>
我尝试过这样的事情并没有按预期工作,我需要帮助:
<?php
$grouping = [];
foreach($albums as $albumName){
//Grouping data by album name
$grouping[$albumName['album_name']][] = $albumName;
}
echo "<pre>";
print_r($grouping);
?>
我觉得我的解决方案还不够,但我缺乏想法。
答案 0 :(得分:1)
尝试这样的事情:
$grouping = [];
foreach($albums as $album) {
if (!isset($grouping[$album['album_id']])) {
$grouping[$album['album_id']] = [
'album_id' => $album['album_id'],
'album_name' => $album['album_name'],
'album_description' => $album['album_description'],
'photos' => []
];
}
$grouping[$album['album_id']]['photos'][$album['photo_id']] = [
'photo_id' => $album['photo_id'],
'photo_name' => $album['photo_name'],
'photo_description' => $album['photo_description']
];
}
演示:http://rextester.com/GBW65553
但通常我只会运行两个查询。首先获取相册并初始化空数组以获取照片。然后获取照片并将其分配到相关相册。
正如@mickmackusa在评论中指出的那样,指数与问题中预期结果的指数不同。这不是一个错误。我就是这样做的。但如果您确实需要与问题完全相同的结果,则可以将代码调整为:
$grouping = [];
foreach($albums as $album) {
if (!isset($grouping[$album['album_name']])) {
$grouping[$album['album_name']] = [
'album_id' => $album['album_id'],
'album_name' => $album['album_name'],
'album_description' => $album['album_description'],
$album['album_name'] => []
];
}
$grouping[$album['album_name']][$album['album_name']][$album['photo_name']] = [
'photo_id' => $album['photo_id'],
'photo_name' => $album['photo_name'],
'photo_description' => $album['photo_description']
];
}