Question

我正在尝试使用API存储体育数据json列，但我无法使其正常工作。虽然我可以插入数据，但它只插入第一列结果并保持它在所有后面的列上重复。默认情况下，它显示50列即将到来的足球比赛。我的问题只是第一行结果是复制..

以下是代码：

//connect to mysql db
$host = "localhost";
$user = "user";
$pass = "pass";
$db = "dname";
$conn = new mysqli($host, $user, $pass, $db) or die("ERROR:could not connect to 
    the database!!!");

//read the json file contents
$url = 'http://api.example.com/v1/events/upcoming?token=566645-
    sl1uDzY3tVvv9M&league_id=78&sport_id=1';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 30);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$data = curl_exec($ch) or die(curl_error($ch));

if ($data === false) {
    $info = curl_getinfo($ch);
    curl_close($ch);
    die('error occured during curl exec. Additioanl info: ' .
            var_export($info));
}
curl_close($ch);
$obj = json_decode($data, true);

foreach ($obj['results'] as $res) {
    $league = $res['league']['name'];
    $home = $res['home']['name'];
    $away = $res['away']['name'];
    $time = date("d/m h:i", $res['time']);
}
$sql = "INSERT INTO schedule(league, home, away, time)
    VALUES('$league', '$home', '$away', '$time')";
$result = mysqli_query($conn, $sql);
if (!$result) {
    die("ERROR :" . mysqli_error());
} else {
    echo "Records has been successfully inserted";
}
//close the connection
mysqli_close($conn);

上面的代码只是插入了第一个json结果，并且它不断重复下一列（结果）..将不胜感激。

Answer 1

您正面临这个问题，因为您正在foreach循环之外执行mysql查询。你必须在循环中执行查询。

执行类似

的操作

foreach ($obj['results'] as $res) 
{ 
$league = $res['league']['name']; 
$home = $res['home']['name']; 
$away = $res['away']['name']; 
$time = date("d/m h:i", 
$res['time']);

$sql = "INSERT INTO schedule(league, home, away, time) VALUES('$league', '$home', '$away', '$time')";
$result=mysqli_query($conn,$sql); 
if(!$result) 
{ 
die("ERROR :". mysqli_error()); 
} else 
{
echo "Records has been successfully inserted";
 } //close the connection mysqli_close($conn);
}

Answer 2

您的插入查询必须如下所示：

foreach ($obj['results'] as $res){
    $league = $res['league']['name'];
    $home = $res['home']['name'];
    $away = $res['away']['name'];
    $time = date("d/m h:i", $res['time']);

    $sql = "INSERT INTO schedule(league, home, away, time)
    VALUES('$league', '$home', '$away', '$time')";
    $result=mysqli_query($conn,$sql);
    if(!$result){
        die("ERROR :". mysqli_error());
    }else{
        echo "Records has been successfully inserted";
    }
}

虽然上述代码可以解决您的问题，但如果您开始使用MySqli 准备好的查询以使其更安全，则会更好。

请点击以下链接了解更多详情：

http://php.net/manual/en/mysqli.quickstart.prepared-statements.php

Answer 3

将插入查询放在foreach循环中。因为你的变量替换了新的foreach结果。 Foreach重新分配你的证据。

foreach ($obj['results'] as $res) {
    $league = $res['league']['name'];
    $home = $res['home']['name'];
    $away = $res['away']['name'];
    $time = date("d/m h:i", $res['time']);

    $sql = "INSERT INTO schedule(league, home, away, time)
    VALUES('$league', '$home', '$away', '$time')";
    $result = mysqli_query($conn, $sql);
    if (!$result) {
        die("ERROR :" . mysqli_error());
    } else {
        echo "Records has been successfully inserted";
    }
}

在MySQL中插入多个JSON列（使用API）

3 个答案:

在MySQL中插入多个JSON列（使用API​​）

3 个答案:

在MySQL中插入多个JSON列（使用API）