Question

在android.googlesource.com上测试了重要运动样本，以了解有关此触发传感器的更多信息。不幸的是，传感器没有触发。我做错了什么？

代码狙击

class TriggerListener extends TriggerEventListener {
    private Context mContext;
    private TextView mTextView;

    TriggerListener(Context context, TextView textView) {
        mContext = context;
        mTextView = textView;
    }

    @Override
    public void onTrigger(TriggerEvent event) {
        if (event.values[0] == 1) {
            mTextView.append(mContext.getString(R.string.sig_motion) + "\n");
            mTextView.append(mContext.getString(R.string.sig_motion_auto_disabled) + "\n");
        }
    }
}

public class MainActivity extends AppCompatActivity {
    private SensorManager mSensorManager;
    private Sensor mSigMotion;
    private TriggerListener mListener;
    private TextView mTextView;

    @Override
    protected void onPause() {
        super.onPause();
        if (mSigMotion != null) mSensorManager.cancelTriggerSensor(mListener, mSigMotion);
    }

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        mSensorManager = (SensorManager)getSystemService(SENSOR_SERVICE);
        mSigMotion = mSensorManager.getDefaultSensor(Sensor.TYPE_SIGNIFICANT_MOTION);
        mTextView = (TextView)findViewById(R.id.text);
        mListener = new TriggerListener(this, mTextView);
        if (mSigMotion == null) {
            mTextView.append(getString(R.string.no_sig_motion) + "\n");
        }
    }

感谢您的帮助。

Answer 1

我遇到了同样的问题，我发现了

mSensorManager.getDefaultSensor(Sensor.TYPE_SIGNIFICANT_MOTION);

返回空值。因此，设备（或虚拟设备）中可能没有重要的运动传感器。在示例中的以下代码中

@Override
protected void onResume() {
    super.onResume();
    if (mSigMotion != null && mSensorManager.requestTriggerSensor(mListener, mSigMotion))
        mTextView.append(getString(R.string.sig_motion_enabled) + "\n");
 }

mSensorManager.requestTriggerSensor(mListener, mSigMotion))从未执行。

触发重要动作需要多少动作

1 个答案: