当我的设备处于4.4.4之下时，我发现问题，我无法理解为什么会出现这样的问题。我尝试找到一些解决方案Why does SQLite say that instr doesnt exist?，所以我猜之前没有function mapToJson(map) {
return JSON.stringify([...map]);
}
之前Android设备版本低于4.4.4
在我的情况下我使用这样的sql： //排序日期：最新到旧日期
INSTR我使用sql是因为我希望public List<Contact> sortingDate() {
List<Contact> contactList = new ArrayList<>();
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE_CONTACTS + " ORDER BY\n" +
" SUBSTR(Date, 1, 4) DESC,\n" +
" CASE WHEN INSTR(SUBSTR(Date, 6), '/') = 2\n" +
" THEN '0' || SUBSTR(Date, 6, 1)\n" +
" ELSE SUBSTR(Date, 6, 2) END DESC,\n" +
" CASE WHEN LENGTH(SUBSTR(SUBSTR(Date, 6), INSTR(SUBSTR(Date, 6), '/') + 1)) = 1\n" +
" THEN '0' || SUBSTR(SUBSTR(Date, 6), INSTR(SUBSTR(Date, 6), '/') + 1)\n" +
" ELSE SUBSTR(SUBSTR(Date, 6), INSTR(SUBSTR(Date, 6), '/') + 1) END DESC; ", null);
//looping through all rows and adding to list
if (cursor.moveToFirst()) {
do {
Contact contact = new Contact();
contact.setID(Integer.parseInt(cursor.getString(0)));
contact.setDate(cursor.getString(1));
contact.setBeforeMorning(cursor.getString(2));
contact.setAfterMorning(cursor.getString(3));
contact.setBeforeNoon(cursor.getString(4));
contact.setAfterNoon(cursor.getString(5));
contact.setBeforeNight(cursor.getString(6));
contact.setAfterNight(cursor.getString(7));
System.out.println("The result is :" + cursor.getString(1));
//Adding contact to list
contactList.add(contact);
} while (cursor.moveToNext());
}
return contactList;
}
如果我的日期类似ORDERBY
yyyy/mm/dd
现在我遇到了问题，如果我再也不能使用2017/2/5，我不知道如何更改我的代码。
我找一些答案说可以使用INSTR，显然它不适合我的情况。
任何帮助将不胜感激。提前谢谢。