Question

客户每日付款交易数据按时间顺序排列：第一列是customerID，第二列是transactionID，它是主键。第三到第五列是TransactionDate，TransactionType和TransactionAmount。 TransactionType可以是具有正TransactionAmount的正常事务（＆＃34; ACH＆＃34;），也可以是具有负TransactionAmount的先前事务的拒绝记录（＆＃34; ACH拒绝＆＃34;）。拒绝通常在3个工作日内发生。我想通过使用CustomID和CustomAmount匹配将拒绝记录映射回其初始事务。

如何在SQL中为大数据集执行此操作？

谢谢！

Answer 1

假设这是元数据和一些适合您业务案例的示例。

CREATE TABLE customer_payment_transaction (
  customerID        bigint NOT NULL, 
  transactionID     bigint PRIMARY KEY, 
  TransactionDate   timestamp NOT NULL, 
  TransactionType   varchar(30) NOT NULL, 
  TransactionAmount decimal(10,2) NOT NULL
);

INSERT INTO customer_payment_transaction 
VALUES 
(1,1, '2017-12-10 09:34:54', 'ACH'            ,   24.88),
(1,2, '2017-12-11 09:34:54', 'ACH'            ,   34.88),
(1,3, '2017-12-12 09:34:54', 'ACH rejections' ,  -34.88),
(2,4, '2017-12-13 09:34:54', 'ACH'            ,   54.88),
(2,5, '2017-12-14 09:34:54', 'ACH'            ,   94.88),
(2,6, '2017-12-15 09:34:54', 'ACH'            ,  104.88),
(2,7, '2017-12-16 09:34:54', 'ACH rejections' ,  -94.88),
(2,8, '2017-12-17 09:34:54', 'ACH rejections' , -104.88),
(1,9, '2017-12-17 10:34:54', 'ACH'            ,   24.88),
(1,10,'2017-12-18 09:34:54', 'ACH rejections' ,  -24.88);

然后解决方案如下

SELECT
      inbound.customerID, 
      inbound.TransactionAmount     AS transaction_amount,
      MIN(inbound.TransactionDate)  AS purchase_date,
      MIN(outbound.TransactionDate) AS reject_date

   FROM       customer_payment_transaction inbound

   INNER JOIN customer_payment_transaction outbound
   ON  outbound.customerID              = inbound.customerID
   AND ABS(outbound.TransactionAmount)  = inbound.TransactionAmount
   AND outbound.TransactionDate         < DATE_ADD(inbound.TransactionDate, INTERVAL 72 HOUR)
   AND outbound.TransactionType         = 'ACH rejections'

   WHERE inbound.TransactionType = 'ACH'

   GROUP BY inbound.customerID,  inbound.TransactionAmount

在http://sqlfiddle.com/

上试用

如果在72小时内有两个出站 OR 两个入站且具有相同的CustomerID, TransactionAmount，则这将不准确。在这些用例中，您将需要其他标识符列，您需要查找或创建这些列。

sql：映射两行

1 个答案: