Question

由于缺少值或空值，我在数组内部进行排序存在问题。

我的代码

SELECT
submission_id,
ARRAY_AGG(question_score) as questions_scores,
SUM(question_score) as groupe_score

FROM(
SELECT
sa.submission_id,
qq.id as question_id,
CASE WHEN SUM(qo.answer_points) > MAX(qq.max_answer_points) THEN MAX(qq.max_answer_points) ELSE SUM(qo.answer_points) END as question_score
FROM selection_answers sa
    inner join question_options qo on qo.id = sa.question_option_id
    inner join questions qq on qq.id = qo.question_id
WHERE qq.task_form_id = 3306 GROUP BY 1,2 ORDER BY sa.submission_id ASC, qq.id ASC ) AS t1 GROUP BY 1

输出：

  submission_id |         questions_scores           |  groupe_score
 -------------------------------------------------------------------
    1034543     | {0,0,0,10,0,10,0,5,0,0,0,5,0,0,0}          |  30
    1034562     | {0,15,15,5,10,0,10,0,5,0,10,10,5,0,0}      |  85
    1034645     | {0,0,10,0,10,0,5,0,10,10,5,0,0}            |  50
    1034699     | {0,0,0,15,5,10,0,10,0,5,0,0,10,10,5,0,0,0} |  70

我在同一个qq.id顺序中的questions_scores中需要相同数量的输出。我尝试过左侧和完全外部连接，但找不到方法。我还创建了一个带有问题表的CTE，并尝试加入此表和CTE中的每一行，但无法弄明白。谢谢你的帮助！

-------编辑表格详情----
问题表栏：

id | max_answer_points

question_options表格列：

id | question_id | answer_points

selection_answer表格列：

id| submission_id| question_option_id

当提交的提交可以在selected_answers中选择多个选项，或者由于与先前所选问题的结果相关的逻辑而跳过问题，因此可能没有答案。我的目标是显示按提交分组的SUM（answer_points）并显示每个问题的数组分数。

Answer 1

我已经解决了。我选择了两次问题表，然后将selection_answers和question_options加入其中一个。这是代码：

SELECT
submission_id,
ARRAY_AGG(question_score) as question_scores,
SUM(question_score) as total_score
FROM(
SELECT
submission_id, qq_id,
SUM(CASE WHEN qq_id=xx_id THEN question_score ELSE 0 END) AS question_score
FROM (
 SELECT
 qq.id as qq_id,
 xx.id as xx_id,
 sa.submission_id,
 CASE WHEN SUM(qo.answer_points) > MAX(xx.max_answer_points) THEN MAX(xx.max_answer_points) ELSE SUM(qo.answer_points) END as question_score
 FROM questions qq, questions xx
     left join question_options qo on qo.question_id = xx.id
     left join selection_answers sa on sa.question_option_id = qo.id
     left join task_forms tf on tf.id = xx.task_form_id
 WHERE qq.task_form_id=3306  AND  xx.task_form_id=3306 
 GROUP BY 1,2,3  ORDER BY sa.submission_id ASC, qq.position ASC, xx.position ASC ) AS t1 GROUP BY 1,2 ORDER BY 1 ASC, 2 ASC ) AS t2
GROUP BY 1

Answer 2

如果我理解正确，您希望每个questions和每个submission_answers都有一个结果，无论是否匹配question_options。

在这种情况下，您应该像这样加入：

FROM (submission_answers sa
      CROSS JOIN questions qq)
     LEFT JOIN question_options qo
        ON qo.id = sa.question_option_id AND qo.question_id = qq.id

您必须处理查询中的NULL值。

要在数组中获得正确的顺序，请使用

array_agg(question_score ORDER BY qq.id) as questions_scores

在Array中排序并将null或0设为缺失值

2 个答案: