解决方案

Question

我正在制作一个程序，有人必须填写一个单词的空白。应该用给定的猜测填充正确的空白，然后该列表继续进行，以便他们可以继续猜测10次尝试。这是一个相对简单的代码。

var department = Mapper.Map<DepartmentEntity, DepartmentViewModel>(departmentEntity,
  opt => opt.AfterMap((src, dest) => dest.Label = src.Labels.FirstOrDefault(x=> 
                                       x.CultureInfo.Name == user.Culture.Name)?.Value));

基本上，我的程序不会多次打印一封信。

E.g。如果我输入“n”，它将不会多次打印“n”，即使“n”在“nonagon”中出现3次。我假设它在“nonagon”中看到第一个“n”，并且只看到那个。

即使他们重复，我怎么会打印信件呢？

Answer 1

wordlist.index(i)在每次迭代中返回i中wordlist的相同（第一次）出现，而不是将for循环替换为：

for p, i in enumerate(wordlist):
    if i == guess:
        blanks[p]=guess
        attempts-=1

Answer 2

解决方案

word = "nonagon"
guessword = ""
for i in word:
    guessword += "_"
for i in range(10):
    guess = raw_input("Take a guess: ")
    guess = guess[0]
    new_guessword = ""
    j = 0
    for ch in word:
        if guess == ch:
            new_guessword += ch
        else:
            new_guessword += guessword[j]
        j += 1
    guessword = new_guessword
    if word == guessword:
        print("You solved it!!")
    else:
        print(guessword)

填写空格不会填写重复字母（简单程序）

2 个答案:

解决方案