Question

我有这个问题：

SELECT DISTINCT 
    CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar) AS ID,
    CONCAT([SIF_DRZAVE].NAZIV_DRZAVE,' - ',CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar),' - Zona I')  AS NAZIV
FROM 
    [dbo].[SV_USLUGA_DRZAVA]
FULL OUTER JOIN 
    [SIF_DRZAVE] ON ([SV_USLUGA_DRZAVA].[ID_DRZAVE]=[SIF_DRZAVE].[ID_DRZAVE]) 
WHERE 
    [SV_USLUGA_DRZAVA].SIF_VRSTA_USLUGA = 139 
    AND ([SV_USLUGA_DRZAVA].ID_DRZAVE = 295 
         OR [SV_USLUGA_DRZAVA].ID_DRZAVE = 293)

UNION ALL

SELECT DISTINCT 
    CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar) AS ID,
    CONCAT([SIF_DRZAVE].NAZIV_DRZAVE,' - ',CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar),' - Zona II') AS NAZIV 
FROM 
    [dbo].[SV_USLUGA_DRZAVA]
FULL OUTER JOIN 
    [SIF_DRZAVE] ON ([SV_USLUGA_DRZAVA].[ID_DRZAVE]=[SIF_DRZAVE].[ID_DRZAVE]) 
WHERE 
    [SV_USLUGA_DRZAVA].SIF_VRSTA_USLUGA = 139 
    AND NOT ([SV_USLUGA_DRZAVA].ID_DRZAVE = 295 
             OR [SV_USLUGA_DRZAVA].ID_DRZAVE = 293)
ORDER BY 
    NAZIV

此查询按'NAZIV'整个声明后的顺序排序。

但我希望在UNION ALL

之前通过'NAZIV'进行查询

Answer 1

您的查询有很多问题。我想这就是你想要的：

SELECT distinct Cast(ud.[ID_DRZAVE] as varchar(255)) as ID,
       CONCAT(d.NAZIV_DRZAVE, ' - ',
              Cast(ud.[ID_DRZAVE] as varchar(255)),
              (CASE WHEN ud.ID_DRZAVE IN (295, 293) THEN ' - Zona I' ELSE ' - Zona II' END)
             ) as NAZIV
FROM [dbo].[SV_USLUGA_DRZAVA] ud JOIN
     [SIF_DRZAVE] d 
     ON ud.[ID_DRZAVE] = d.[ID_DRZAVE]
WHERE d.SIF_VRSTA_USLUGA = 139 
ORDER BY (CASE WHEN ud.ID_DRZAVE IN (295, 293) THEN 1 ELSE 0 END),
         NAZIV;

注意：

FULL JOIN条款正在取消WHERE。使用适当的JOIN。
使用IN而不是链接OR条件。
永远不要在SQL Server中使用VARCHAR()没有长度。默认长度因上下文而异，调试此问题可能非常具有挑战性。
表别名使查询更易于编写和阅读。
根据您的目标，您根本不需要UNION / UNION ALL。

Answer 2

添加另一列，以便获得所需的订单：

SELECT DISTINCT 
    '1' AS ZONA,
    CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar) AS ID,
    CONCAT([SIF_DRZAVE].NAZIV_DRZAVE,' - ',CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar),' - Zona I')  AS NAZIV
FROM 
    [dbo].[SV_USLUGA_DRZAVA]
FULL OUTER JOIN 
    [SIF_DRZAVE] ON ([SV_USLUGA_DRZAVA].[ID_DRZAVE]=[SIF_DRZAVE].[ID_DRZAVE]) 
WHERE 
    [SV_USLUGA_DRZAVA].SIF_VRSTA_USLUGA = 139 
    AND ([SV_USLUGA_DRZAVA].ID_DRZAVE = 295 
        OR [SV_USLUGA_DRZAVA].ID_DRZAVE = 293)
UNION ALL
SELECT DISTINCT 
    '2',
    CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar) AS ID,
    CONCAT([SIF_DRZAVE].NAZIV_DRZAVE,' - ',CAST([SV_USLUGA_DRZAVA].[ID_DRZAVE] AS varchar),' - Zona II') AS NAZIV 
FROM 
    [dbo].[SV_USLUGA_DRZAVA]
FULL OUTER JOIN 
    [SIF_DRZAVE] ON ([SV_USLUGA_DRZAVA].[ID_DRZAVE]=[SIF_DRZAVE].[ID_DRZAVE]) 
WHERE 
    [SV_USLUGA_DRZAVA].SIF_VRSTA_USLUGA = 139 
    AND NOT ([SV_USLUGA_DRZAVA].ID_DRZAVE = 295 
         OR [SV_USLUGA_DRZAVA].ID_DRZAVE = 293)
ORDER BY 
    ZONA, NAZIV

UNION ALL之前的语句中的ORDER BY

2 个答案: