我使用Ionic 3开发了一个PWA(基于Tab)。它在Android浏览器中按下硬件后退按钮或浏览器的后退按钮之前工作正常。如果它从主屏幕运行,按回硬件将关闭应用程序。如果应用程序在android中运行chrome(仅在chrome中测试),硬件返回或浏览器的后面将重新加载PWA的第一页,而不是以前访问过的页面。如何在Ionic 3 PWA中处理这些事件?
我正在为所有页面使用延迟加载。
到目前为止我尝试了什么:
根据jgw96的评论here,我认为IonicPage将自己处理导航。但它没有用。
使用了platform.registerBackButtonAction,但它不适用于PWA。
根据Webruster在Answers中的建议,尝试了app.component.ts中的代码。但没有变化。
发布代码:
import { Component, ViewChild } from '@angular/core';
import { Nav, Platform, AlertController, Alert, Events, App, IonicApp, MenuController } from 'ionic-angular';
@Component({
templateUrl: 'app.html'
})
export class MyApp {
@ViewChild(Nav) nav: Nav;
rootPage:any = 'TabsPage';
constructor(public platform: Platform,
public alertCtrl: AlertController, public events: Events,
public menu: MenuController,
private _app: App,
private _ionicApp: IonicApp) {
platform.ready().then(() => {
this.configureBkBtnprocess ();
});
}
configureBkBtnprocess() {
if (window.location.protocol !== "file:") {
window.onpopstate = (evt) => {
if (this.menu.isOpen()) {
this.menu.close ();
return;
}
let activePortal = this._ionicApp._loadingPortal.getActive() ||
this._ionicApp._modalPortal.getActive() ||
this._ionicApp._toastPortal.getActive() ||
this._ionicApp._overlayPortal.getActive();
if (activePortal) {
activePortal.dismiss();
return;
}
if (this._app.getRootNav().canGoBack())
this._app.getRootNav().pop();
};
this._app.viewDidEnter.subscribe((app) => {
history.pushState (null, null, "");
});
}
}
}
答案 0 :(得分:6)
你提到你正在使用应用程序和浏览器中的硬件后退按钮,所以你没有清楚地提到在什么阶段需要做什么,所以我想出了广泛的解决方案,这在大多数情况下是有用的案件
<强> app.component.ts 强>
platform.ready().then(() => {
// your other plugins code...
this.configureBkBtnprocess ();
});
configureBkBtnprocess
private configureBkBtnprocess () {
// If you are on chrome (browser)
if (window.location.protocol !== "file:") {
// Register browser back button action and you can perform
// your own actions like as follows
window.onpopstate = (evt) => {
// Close menu if open
if (this._menu.isOpen()) {
this._menu.close ();
return;
}
// Close any active modals or overlays
let activePortal = this._ionicApp._loadingPortal.getActive() ||
this._ionicApp._modalPortal.getActive() ||
this._ionicApp._toastPortal.getActive() ||
this._ionicApp._overlayPortal.getActive();
if (activePortal) {
activePortal.dismiss();
return;
}
// Navigate back
if (this._app.getRootNav().canGoBack())
this._app.getRootNav().pop();
}
else{
// you are in the app
};
// Fake browser history on each view enter
this._app.viewDidEnter.subscribe((app) => {
history.pushState (null, null, "");
});
解决方案2 尝试在准备好的平台中添加这些事件监听器:
window.addEventListener('load', function() { window.history.pushState({}, '')
})
window.addEventListener('popstate', function() { window.history.pushState({},
'') })
答案 1 :(得分:0)
我有几乎相同的要求,但是没有一种解决方案能完全起作用,所以我提出了自己的解决方案。在这里,我使用了一个数组来跟踪已访问页面,并在发生单击事件时将其删除。
注意:import { Platform, Nav } from "ionic-angular";
import { HomePage } from "../pages/home/home";
@Component({
templateUrl: "app.html"
})
export class MyApp {
rootPage: any;
@ViewChild(Nav) nav: Nav;
pageHistory: string[] = [];//to track page history
constructor(
platform: Platform,
statusBar: StatusBar,
splashScreen: SplashScreen
) {
window.addEventListener("load", function() {
//adding a state to prevent app exit on back
window.history.pushState({ noBackExitsApp: true }, "");
});
platform.ready().then(() => {
window.onpopstate = evt => {
let view = this.nav.getActive();
if (this.pageHistory.find(x => x === view.name)) {
if (!view.name.startsWith("Home")) {//handle a condition where you want to go back
this.pageHistory = this.pageHistory.filter(n => n !== view.name);
this.nav.pop().catch(reason => {
console.log("Unable to pop :" + reason);
});
}
} else {
window.history.pushState({ noBackExitsApp: true }, "");
this.pageHistory.push(view.name);
}
};
this.rootPage = HomePage;
statusBar.styleDefault();
splashScreen.hide();
});
}
}
即使在推送新页面时也会被调用
file_names = ["#{fileNameFromUser}"]
file_names.each do |file_name|
text = File.read(file_name)
replacedcontent = text.gsub(/textToReplace/, "#{ReplaceWithThis}")
replacedcontent += text.gsub(/textToReplace2/, "#{ReplaceWithThis2}")
# To write changes to the file, use:
File.open(file_name, "w") {|file| file.puts replacedcontent}
end