Question

public class assignment2
{
    public static void main(String[] args) throws IOException 
    {
        // TODO Auto-generated method stub
        FileInputStream fstream = new FileInputStream("assignment2.txt");
        BufferedReader br = new BufferedReader(new InputStreamReader(fstream));

        String strLine;

        //Read File Line By Line
        while ((strLine = br.readLine()) != null) {
            // Print the content on the console
            System.out.println (strLine);
            String[] numbers = strLine.split(" ");
            System.out.print(numbers[1]);
        }
        //Close the input stream
        br.close();
    }
}

我希望代码会将String []数字打印为 1 0 10

我得到的结果是00371010

请注意输入文件的格式如下：

1 0 10

2 0 9

3 3 5

4 7 4

5 10 6

6 10 7

Answer 1

只需更换你的行：

System.out.print(numbers[1]);

使用：

for (int i = 0; i < numbers.length; i++)
    System.out.print(numbers[i] + " ");

System.out.println();

让我知道它是如何运作的。

Answer 2

您需要通过添加另一个循环来修改代码：

public static void main(String[] args) throws IOException {
    // TODO Auto-generated method stub
    FileInputStream fstream = new FileInputStream("assignment2.txt");
    BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
    String strLine;

    //Read File Line By Line
    while ((strLine = br.readLine()) != null){
        // Print the content on the console
        System.out.println (strLine);
        String[] numbers = strLine.split(" ");
        for (String num : numbers){
            System.out.print(num + " ");
        }
        System.out.println("\n");
    }
    //Close the input stream
    br.close();
}

因为，数字[1]只会打印索引1处的值。

如何读取一行上的每个int的.txt文件。存储到数组？

2 个答案: