Question

我希望这句话能够返回有两个以上站点的系统，我已经做到了这一点，但我不知道下一步该做什么。所有这一切都会返回每个系统，其区域ID小于1100001.我至少是正确的想法吗？

SELECT DISTINCT mapSolarSystems.regionID,solarSystemID,solarSystemName,x,z,security 
FROM mapSolarSystems 
WHERE mapSolarSystems.regionID <11000001  
AND 
2 < (SELECT COUNT(*) FROM stations,mapSolarSystems
 WHERE mapSolarSystems.solarSystemID=stations.systemid)

Answer 1

看看这是否有效：

SELECT DISTINCT mapSolarSystems.regionID,solarSystemID,solarSystemName,x,z,security 
FROM mapSolarSystems m
join stations s on m.solarSystemID = s.systemid
WHERE mapSolarSystems.regionID <11000001  
AND select COUNT(*) FROM stations >2

或者那样：

SELECT DISTINCT 
mapSolarSystems.regionID,solarSystemID,solarSystemName,x,z,security 
FROM mapSolarSystems m
join (select sistemId ,count(systemid) from station group by sistemId having 
      count(sistemId) > 2) X on m.solarSystemID = X.systemid
WHERE mapSolarSystems.regionID <11000001

Answer 2

SELECT DISTINCT m.regionID，solarSystemID，solarSystemName，x，z，security FROM mapSolarSystems m m.solarSystemID = s.systemid中的m个连接站WHERE m.regionID＆lt; 11000001 AND（SELECT COUNT（*）FROM stations）＆gt ; 2

SQL语句中的SQL语句

2 个答案: