Question

我在这里收到此错误（无法为类型＆＃39; Double＆＃39;调用类型＆＃39;（范围）＆＃39;）的参数列表调用初始化程序

for dista in Double(0..<(car.distance)) //error here {

        }

其中＆＃34;距离＆＃34;是Double类型。我怎么解决呢？

更新

var距离：双倍？是一个定制的班级＆＃34; Car＆＃34;。我有一个功能，为我下载不同的汽车

    if let carsDownloaded = response.cars {
                    var number = cars / (models?.count)!
                    number = number == 0 ? 1 : number

                    let distanceC = carsDownloaded

         for car in distanceC {
                        for dista in car.distance! { 
   }
 }

汽车是我可以下载的汽车，如果我真的可以下载这些汽车的响应选择，最后response.cars是我将下载的汽车。现在我想在过滤器中订购那些离最近最公平的汽车，但我的问题是我从我的位置到具有外部功能的X车的距离值

func distance(from: CLLocationCoordinate2D, to: CLLocationCoordinate2D) -> CLLocationDistance {
        let from = CLLocation(latitude: from.latitude, longitude: from.longitude)
        let to = CLLocation(latitude: to.latitude, longitude: to.longitude)

        return from.distance(from: to)

    }


    func didSelectt(car:Car) {

        guard let coordinates = car.location  else {
            return
        }
        self.destination = coordinates

        // update distance
        if currentLocation != nil {
            let dist = distance(from: currentLocation!, to: coordinates)
        }
    }

Answer 1

循环中in参数的类型必须是Int的范围。此外，您无法将范围转换为单类型，例如Double

迭代序列！= Int您需要stride

let distance = 25.0

for dista in stride(from:0.0, to: distance, by: 1.0) {
    print(dista)
}

无法为类型＆＃39; Double＆＃39;调用初始化程序。使用类型＆＃39;（范围<double>）＆＃39;

1 个答案: