当我索引我的关系数据库(Postgresql)时,我想得到外键id的字符串值intead(重新创建两个表personn和country之间的关系..) 我希望在fos_elastica.yml映射文件中执行此操作
示例:
fos_elastica:
clients:
default: { host: %elastic_host%, port: %elastic_port% }
indexes:
ex_app:
client: default
types:
personn:
mappings:
id:
type: integer
name:
type: text
boost: 5
firstname:
type: text
boost: 3
dateofbirth:
type: date
country:
type: integer
persistence:
driver: orm
model: AppBundle\Entity\Personn
finder: ~
provider: ~
listener: ~
我想通过输入国家名称而不是国家/地区ID来找到此人。
答案 0 :(得分:0)
我很确定你应该使用“嵌套”:
fos_elastica:
clients:
default: { host: %elastic_host%, port: %elastic_port% }
indexes:
ex_app:
client: default
types:
personn:
mappings:
id:
type: integer
name:
type: text
boost: 5
firstname:
type: text
boost: 3
dateofbirth:
type: date
country:
type: "nested"
properties:
id:
type : integer
label:
type: text
persistence:
driver: orm
model: AppBundle\Entity\Personn
finder: ~
provider: ~
listener: ~