Question

我觉得我已经尝试了一切来使这个工作，它只是不会运行... 我还在学习python，我的课程在几个月前就开始了秋天的开始。

长话短说，我正在使用Python制作基于文本的“逃离房间”游戏。玩家选择要与之交互的对象，结果会让他们使用项目，直到他们找到解锁门的钥匙。为了节省我的理智，它非常简短和线性。

我认为这是我的代码中没有运行的部分，它是一个包含所有4个对象的类似代码的大函数（对不起，如果它有点长。

这基本上都是这样，“当他们选择这幅画时，如果他们想要搜索它们，请描述它，（1 =是，2 =否）。

如果有，请描述搜索结果。因为这是故事的最后一个对象（绘画背后的安全有门钥匙），一旦打开保险箱并且他们有钥匙，我不希望它再次向他们询问主要问题，但确实如此！？< / p>

重复的主要问题是;

def main_choice_input():
    main_choice = input("""
What would you like to check out? (1=Bed, 2=Desk, 3=Dresser, 4=Painting): """) 
    return main_choice;

#code for describing the objects, the inputs for the player to search them
#and the search results, if tried to name them as self-explanatory as 
#possible

以前的格式用于其他对象，这是一个很大的功能。

while main_choice == "4":
    painting_description()
    #painting_input is the "search this?" question
    painting_input = painting_interaction()
    if painting_input =="1":
        painting_search(painting_input,dresser_input)
    if use_key=="1" and painting_input =="1":
       #If they 'used the key' on the desk to get the code:
        painting_search(painting_input,dresser_input)
        unlock = input("""
Would you like to unlock the safe? [1=Yes/2=No]: """)
        if unlock == "1":

            #print (story for opening the safe)

            safe=1 #for ending the game- checking if the safe is open
        if unlock == "2":
           print("""
    That's too bad, let's try again...""")
           main_choice = main_choice_input()
           main_route(main_choice,bed_input,desk_input,dresser_input,
            painting_input,use_key,)
    if painting_input =="2":
        print("""
    The code must be around here somewhere... Let's keep looking!
        """)
       #main_route is the name of this whole function
        main_choice = main_choice_input()
        main_route(main_choice,bed_input,desk_input,
         dresser_input,painting_input,use_key,)
   #I had it re-ask and re-run here too, so if they dont have the code/choose not to search or whatever, they can go back and get it
    break
   while main_choice != "1" or main_choice != "2" or main_choice != "3" or 
main_choice != "4":
    main_choice = main_choice_input()
    main_route(main_choice,bed_input,desk_input,dresser_input,painting_input,use_key,)
 return;

我的问题是这个程序甚至没有运行unlock = input函数，它会播放搜索描述然后询问主要的“你想要签出什么”这样的问题;

 Take a look? [1=Yes/2=No]

1

    You walk up and inspect the painting as if it were displayed in a museum.
It's clearly just a copy of the painting, not even trying to be the real thing.
You begin to notice that the painting is hanging a couple inches off the wall...


    You grab the painting on either side of the frame, and gently place it on
the floor, revealing a safe built into the wall!


What would you like to check out? (1=Bed, 2=Desk, 3=Dresser, 4=Painting):

而不是最后一个问题，应该问我是否要打开保险箱，因为我得到了代码，但事实并非如此？为什么？请帮忙，我很失落和沮丧。

嵌套/ /如果程序跳过代码？

0 个答案: