我已经搜索了很多关于BeautifulSoup的内容,有些人认为lxml是BeautifulSoup的未来,虽然这很有意义,但我很难从网页上的整个表格列表中解析下表。
我对具有不同行数的三列感兴趣,具体取决于页面和检查时间。非常感谢BeautifulSoup和lxml解决方案。这样我可以要求管理员在dev上安装lxml。机。
期望的输出:
Website Last Visited Last Loaded
http://google.com 01/14/2011
http://stackoverflow.com 01/10/2011
...... more if present
以下是来自凌乱网页的代码示例:
<table border="2" width="100%">
<tbody><tr>
<td width="33%" class="BoldTD">Website</td>
<td width="33%" class="BoldTD">Last Visited</td>
<td width="34%" class="BoldTD">Last Loaded</td>
</tr>
<tr>
<td width="33%">
<a href="http://google.com"</a>
</td>
<td width="33%">01/14/2011
</td>
<td width="34%">
</td>
</tr>
<tr>
<td width="33%">
<a href="http://stackoverflow.com"</a>
</td>
<td width="33%">01/10/2011
</td>
<td width="34%">
</td>
</tr>
</tbody></table>
答案 0 :(得分:4)
>>> from lxml import html
>>> table_html = """"
... <table border="2" width="100%">
... <tbody><tr>
... <td width="33%" class="BoldTD">Website</td>
... <td width="33%" class="BoldTD">Last Visited</td>
... <td width="34%" class="BoldTD">Last Loaded</td>
... </tr>
... <tr>
... <td width="33%">
... <a href="http://google.com"</a>
... </td>
... <td width="33%">01/14/2011
... </td>
... <td width="34%">
... </td>
... </tr>
... <tr>
... <td width="33%">
... <a href="http://stackoverflow.com"</a>
... </td>
... <td width="33%">01/10/2011
... </td>
... <td width="34%">
... </td>
... </tr>
... </tbody></table>"""
>>> table = html.fromstring(table_html)
>>> for row in table.xpath('//table[@border="2" and @width="100%"]/tbody/tr'):
... for column in row.xpath('./td[position()=1]/a/@href | ./td[position()>1]/text() | self::node()[position()=1]/td/text()'):
... print column.strip(),
... print
...
Website Last Visited Last Loaded
http://google.com 01/14/2011
http://stackoverflow.com 01/10/2011
>>>
瞧;) 当然,您可以将值添加到嵌套列表或dicts中,而不是打印;)
答案 1 :(得分:3)
这是一个使用elementtree的版本及其提供的有限XPath:
from xml.etree.ElementTree import ElementTree
doc = ElementTree().parse('table.html')
for t in doc.findall('.//table'):
# there may be multiple tables, check we have the right one
if t.find('./tbody/tr/td').text == 'Website':
for tr in t.findall('./tbody/tr/')[1:]: # skip the header row
tds = tr.findall('./td')
print tds[0][0].attrib['href'], tds[1].text.strip(), tds[2].text.strip()
结果:
http://google.com 01/14/2011
http://stackoverflow.com 01/10/2011
答案 2 :(得分:2)
这是一个使用HTMLParser的版本。我试图反对pastebin.com/tu7dfeRJ的内容。它处理元标记和doctype声明,这两个声明都挫败了ElementTree版本。
from HTMLParser import HTMLParser
class MyParser(HTMLParser):
def __init__(self):
HTMLParser.__init__(self)
self.line = ""
self.in_tr = False
self.in_table = False
def handle_starttag(self, tag, attrs):
if self.in_table and tag == "tr":
self.line = ""
self.in_tr = True
if tag=='a':
for attr in attrs:
if attr[0] == 'href':
self.line += attr[1] + " "
def handle_endtag(self, tag):
if tag == 'tr':
self.in_tr = False
if len(self.line):
print self.line
elif tag == "table":
self.in_table = False
def handle_data(self, data):
if data == "Website":
self.in_table = 1
elif self.in_tr:
data = data.strip()
if data:
self.line += data.strip() + " "
if __name__ == '__main__':
myp = MyParser()
myp.feed(open('table.html').read())
希望这可以解决您需要的一切,您可以接受这个作为答案。 根据要求更新。