Question

我想以JSON格式显示数据

我想以JSON格式显示if和else语句数据

        foreach($share_amount as $value)
        {
         if($value<$total_avg){
          $a= $total_avg-$value; 
          $data2['pay_amount'] = $a;   
          $data2['member_id'] = $detail;
          $data2['contribution_response'] = "Need to pay"; 
         }
         else
         {
         $b= $total_avg-$value; /* the share amount stored and calculated*/
        ....
         $data2['contribution_response'] = "Need to take";
         }
         echo json_encode(array($data2));  
         /*storing in json but not getting displayed in the format*/

Answer 1

json_encode（）示例并使用JSON_FORCE_OBJECT：

<?php
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);

echo json_encode($arr,JSON_FORCE_OBJECT);
?>

根据您的代码

## I want to display the data in json format ##
        $data2 = array();
        foreach($share_amount as $value)
        {
             if($value<$total_avg){
                  $a= $total_avg-$value; 
                  $data2['pay_amount'] = $a;   
                  $data2['member_id'] = $detail;
                  $data2['contribution_response'] = "Need to pay"; 
              }
              else
             {
                 $b= $total_avg-$value; /* the share amount stored and calculated*/

                 $data2['contribution_response'] = "Need to take";
             }
        }
         echo json_encode($data2, JSON_FORCE_OBJECT);  /*storing in json but not getting displayed in the format*/

Answer 2

您的代码中有一个array()类型变量，它总是重新分配给特定值，尝试使用[]为新数组值进行自动分区。

 $data2 = array();    

    foreach($share_amount as $value)
    {
        $tmp_array = array();
         if($value < $total_avg){
              $a= $total_avg - $value; 
              $tmp_array['pay_amount'] = $a;   
              $tmp_array['member_id'] = $detail;
              $tmp_array['contribution_response'] = "Need to pay"; 
          }
          else
         {
             $b = $total_avg - $value; /* the share amount stored and calculated*/

             $tmp_array['contribution_response']= "Need to take";
         }
         $data2[]['anytime'] = $tmp_array;
    }
    echo json_encode($data2);

Answer 3

您需要构建一个数组数组 - 对于循环中的每次迭代，您需要将结果作为数组添加到输出对象（$payload），然后在结束时对其进行编码。

$payload=array();
foreach($share_amount as $value){
    $data=array();
    if( $value < $total_avg ){
        $a=$total_avg-$value; 

        $data['pay_amount'] = $a;   
        $data['member_id'] = $detail;
        $data['contribution_response'] = "Need to pay";

        $payload[]=$data;
    } else {
        $b=$total_avg-$value;
        $data['pay_amount']=$b;
        $data['member_id'] = '';
        $data['contribution_response']="Need to take";
    }
}
echo json_encode( $payload );

Answer 4

This is how I got the answer
     foreach($share_amount as $value)
        {
             if($value<$total_avg){
                $a= $total_avg-$value;

        $data2['pay_amount'] = $a;   
        $data2['member_id'] = $detail;
        $data2['contribution_response'] = "Need to pay";
         }
         else
             {
        $b= $total_avg-$value;
        $edata['pay_amount'] = $b;   
        $edata['member_id'] = $detail;
        $edata['contribution_response'] = "Need to take";
         //echo json_encode($data2);

            }
            echo "\n";

        }
         echo json_encode(array($data2,$edata));

如何以JSON格式显示值？

4 个答案: