我遇到了valgrind和C的麻烦。我不知道为什么,但是valgrind这样说:
== 18241 ==读取大小为1
== 18241 ==在0x4C31A64:strcmp(vg_replace_strmem.c:846)
== 18241 == by 0x403110:lastLetters(diccionario.c:1330)
== 18241 ==地址0x520c5b3在大小为3的块之后为0字节
== 18241 ==在0x4C2DBF6:malloc(vg_replace_malloc.c:299)
== 18241 == by 0x402ED0:lastLetters(diccionario.c:1284)
我有一个带链表的动态矩阵,其中每一行都是一个字母,每列都是一个单词。在列表的节点中,我想要比较它们之间的单词,但只是比较每个单词的最后3个字母。
矩阵示例:
Black Blue Blondie BlackOut
绿色灰色水
Crimsom Color Clue
例如Blue&线索最后3个字母相同:lue。
这是我的代码,valgrind说:
第1284行=> lastLettersList = malloc(sizeof(char)* 3);
第1330行=> if(strcmp(lastLettersList,lastLettersList2)== 0)
char* lastLettersList;
char* lastLettersList2;
int wordLen = 0;
int maxCount = 0;
int count = 0;
for (int i = 0; i < matrixSpanish->rows; ++i)
{
node* current = matrixSpanish->list[i]->start;
while(current!=NULL)
{
wordLen = strlen(current->word);
count = 0;
if( wordLen > 2)
{
lastLettersList = malloc(sizeof(char)*3);
lastLettersList[2] = current->word[wordLen-1];
lastLettersList[1] = current->word[wordLen-2];
lastLettersList[0] = current->word[wordLen-3];
}
}
for (int j = 0; j < matrixSpanish->rows; ++j)
{
node* current2 = matrixSpanish->list[j]->start;
while(current2!=NULL)
{
wordLen = strlen(current2->word);
if( wordLen > 2)
{
lastLettersList2 = malloc(sizeof(char)*3);
lastLettersList2[2] = current2->word[wordLen-1];
lastLettersList2[1] = current2->word[wordLen-2];
lastLettersList2[0] = current2->word[wordLen-3];
}
if (strcmp(lastLettersList,lastLettersList2) == 0)
{
count++;
}
current2=current2->nextNode;
}
}
current=current->nextNode;
}
答案 0 :(得分:0)
您没有为要复制的子字符串分配足够的空间。 lastLettersList
不包含终止空字节(也没有为它分配空间),因此从技术上讲它不是字符串而是字符数组。
然后尝试使用strcmp
上的字符串函数lastLettersList
,它不是字符串,并且读取数组的末尾,这是Valgrind警告的内容。读取数组末尾会调用未定义的行为。
为lastLettersList
分配一个额外字节,并将空字节放在最后。
lastLettersList = malloc(sizeof(char)*4);
lastLettersList[3] = 0;
lastLettersList[2] = current->word[wordLen-1];
lastLettersList[1] = current->word[wordLen-2];
lastLettersList[0] = current->word[wordLen-3];