在MapReduce应用程序中,我有一个名为AnonymousPair的任意WritableComparable实现,我注意到了这个
import com.google.common.collect.MinMaxPriorityQueue;
public static class MyReducer extends Reducer<LongWritable, AnonymousPair, LongWritable, Text> {
@Override
protected void reduce(LongWritable key, Iterable<AnonymousPair> values, Context context) throws IOException, InterruptedException {
// ...
MinMaxPriorityQueue<AnonymousPair> pQueue = MinMaxPriorityQueue
.orderedBy(new AnonymousPair().comparator())
.maximumSize(Constants.MaxKeywords)
.create();
for(AnonymousPair val : values) {
pQueue.add(new AnonymousPair(val)); // No problem with copy constructor
// pQueue.add(val); // Wrong! Every element in pQueue will be the same
}
}
}
如果我不使用复制构造函数&#39;,pQueue中的每个元素最终都是相同的。谁能帮我理解这个?谢谢! 我的猜测是
我的AnonymousPair实施
public static class AnonymousPair implements WritableComparable<AnonymousPair> {
private String a = "";
private Float b = 0f;
public AnonymousPair() {}
public AnonymousPair(String a, Float b) {this.a = a; this.b = b;}
public AnonymousPair(AnonymousPair o) {this.a = o.a; this.b = o.b;}
public Comparator<AnonymousPair> comparator() {return new AnonymousPairComparator();}
class AnonymousPairComparator implements Comparator<AnonymousPair> {
@Override
public int compare(AnonymousPair o1, AnonymousPair o2) {
Float diff = o1.b - o2.b;
if(diff == 0) {
return 0;
}
if(diff < 0) {
return 1; // Reverse order
} else {
return -1;
}
}
}
@Override
public int compareTo(AnonymousPair o) {
int temp = this.a.compareTo(o.a);
if(temp == 0) {
return -this.b.compareTo(o.b);
} else {
return temp;
}
}
// More overriding...
}
答案 0 :(得分:1)
请参阅javadoc:
框架将重用传递的键和值对象 进入reduce,因此应用程序应克隆对象 他们想保留一份副本。在许多情况下,所有值都合并在一起 分为零或一个值。