Question

我正在尝试使用两个不同的查询在PHP中构建一个2d数组。由于某种原因，页面未显示有关发生的任何错误的任何消息。它就像数组不存在一样反应。

因此我假设它，因为我没有正确处理数组。

这是代码：

$stuarr= array();        ***//the 2d array initialization***

$query1 = "SELECT * FROM students WHERE userid= '$uid' ORDER BY name"; 
$stulist = mysqli_query($conn,$query1) or die ("cannot query the table1 " .mysqli_error($conn)); 
while ($students = mysqli_fetch_array($stulist)) {
    ${$students['name']}= array();   ******//the inside array initialization...the one that will insert to $stuarr***

    $count=$_SESSION['counter'];
    $sname=$students['name'];
    $query3 = "SELECT * FROM ranks WHERE userid= '$uid' AND rankers='$sname' ORDER BY therate DESC"; 
    $stur = mysqli_query($conn,$query3) or die ("cannot query the table1 " .mysqli_error($conn));
    while ($sturank = mysqli_fetch_array($stur) && !$count==0) {

        array_push(${$students['name']},$sturank['rated']);
        $count=$count-1;
        print_r(${$students['name']});
    }

    array_push($stuarr,${$stulist['name']});
    print_r($stuarr);  ***///this print is showing nothing***
}

我很想听听您对代码的看法。

谢谢你！

Answer 1

更改

df.query("Class == 'Class1' |  Class == 'Class2'")
#here working or too
#df = df.query("Class == 'Class1' or  Class == 'Class2'")

到

array_push($stuarr,${$stulist['name']});

为什么PHP中的2d数组处理不好？

1 个答案: