基本上我希望能够在循环迭代中告诉我何时在第N个项目上。 有什么想法吗?
d = {1:2, 3:4, 5:6, 7:8, 9:0}
for x in d:
if last item: # <-- this line is psuedo code
print "last item :", x
else:
print x
答案 0 :(得分:29)
使用enumerate
:
#!/usr/bin/env python
d = {1:2, 3:4, 5:6, 7:8, 9:0}
# If you want an ordered dictionary (and have python 2.7/3.2),
# uncomment the next lines:
# from collections import OrderedDict
# d = OrderedDict(sorted(d.items(), key=lambda t: t[0]))
last = len(d) - 1
for i, x in enumerate(d):
if i == last:
print i, x, 'last'
else:
print i, x
# Output:
# 0 1
# 1 3
# 2 9
# 3 5
# 4 7 last
答案 1 :(得分:3)
如何使用enumerate?
>>> d = {1:2, 3:4, 5:6, 7:8, 9:0}
>>> for i, v in enumerate(d):
... print i, v # i is the index
...
0 1
1 3
2 9
3 5
4 7
答案 2 :(得分:3)
for x in d.keys()[:-1]:
print x
if d: print "last item:", d.keys()[-1]
答案 3 :(得分:0)
d = {1:2, 3:4, 5:6, 7:8, 9:0}
for i,x in enumerate(d):
print "last item :"+repr(x) if i+1==len(d) else x
但无序词典的最后一项并不意味着什么
答案 4 :(得分:0)
list = [1,2,3]
last = list[-1]
for i in list:
if i == last:
print("Last:")
print i
输出:
1
2
Last:
3