Question

目前在游戏中，它会询问某些问题，例如，你收集了所有的钥匙，杀死了所有的老板等。但是当它接近结束时它会询问“你想使用哪个键？”。它做得很好，但一旦到达门部分，它实际上并没有得到键的值，它只输出0

主要代码

public static int possibleKey()
{            
    SetnGet sng = new SetnGet();
    int keys;
    do
    {   
        System.out.println("Which key would you like to use?");
        keys = in.nextInt();
         }
     while(keys != 1 && keys != 2 && keys != 3);

    return keys;
}

public static int possibleLevel()
{
    SetnGet sng = new SetnGet();
    System.out.println("Which door would you like to enter? - 1, 2, 3 or 4");
    int level;  

    if(sng.accessibleKey() == 3)
    {
        do
        {   
            System.out.println("You have all three keys, you have complete access");
            level = in.nextInt();
        }
        while(level != 1 && level != 2 && level != 3);
    }
    else
    {
        do
        {   
            System.out.println("You have no level access");
            level = in.nextInt();
        }
        while(level != 1 && level != 2 && level != 3 && level != 4);

    }
    return level;
}

Set和Get来自SetnGet Class

private int possibleKey;
private int possibleLevel;

public int setPossibleKey()
{
    return possibleKey;
}

public void setPossibleKey(int possibleKey)
{
    this.possibleKey = possibleKey;
}

public int getPossibleLevel()
{
    return possibleLevel;
}

public void setPossibleLevel(int possibleLevel)
{
    this.possibleLevel = possibleLevel;
}

Answer 1

方法possibleLevel()创建SetnGet类（SetnGet sng = new SetnGet();）的实例，然后读取实例类型int的字段{{1} }}）。这种读取的结果当然是0，因为这是sng.accessibleKey()类字段的默认值，您永远不会为您的字段设置任何其他值。因此，您总是转到int并查看＆＃34;您没有等级访问权限＆＃34;消息。

可以做什么来解决问题的方法是将else从SetnGet sng = new SetnGet();移到课堂上，然后确保possibleLevel()来电的结果是设置它，像这样：

possibleKey()

public class Main { private static Scanner in = new Scanner(System.in); private static SetnGet sng = new SetnGet(); public static void main(String[] args) { int selectedKey = possibleKey(); sng.accessibleKey(selectedKey); int level = possibleLevel(); } public static int possibleKey() { // your initial implementation of the method } public static int possibleLevel() { // your initial implementation of the method, but // without the "SetnGet sng = new SetnGet();" line } }类看起来像这样：

SetnGet

这将解决您的初始问题。然后你可以考虑进一步重构代码，例如，使用方法参数（而不是共享类字段）在方法之间传递数据，从class SetnGet { private int accessibleKey; int accessibleKey() { return accessibleKey; } void accessibleKey(int accessibleKey) { this.accessibleKey = accessibleKey; } }方法中除去冗余的SetnGet sng = new SetnGet();行等等。

创建一个基于文本的游戏，我被困住了

1 个答案: