Question

我有一个服务器URL的二维列表，其格式为

[["John",5,7,"something1"],
["David",4,2,"something2"],etc]

有没有一种快速的方法可以将此列表解析为具有指定密钥对的正确JSON格式，如下所示？

[{name:"John", 
numbercolumn1:5,
numbercolumn2:7,
description:"something1"},
{},{}]

Answer 1

如果这些都属于您的属性，则可以使用Array#map()，如下所示：

var data = arr.map(function(a) {
  return {
    name: a[0],
    columnNumber1: a[1],
    columnNumber2: a[2],
    description: a[3]
  };
});

<强>演示：

var arr = [
  ["John", 5, 7, "something1"],
  ["David", 4, 2, "something2"]
];

var data = arr.map(function(a) {
  return {
    name: a[0],
    columnNumber1: a[1],
    columnNumber2: a[2],
    description: a[3]
  };
});

console.log(data);

Answer 2

您可以先创建一个包含对象属性名称的数组。
之后，您可以使用Array.prototype.map迭代列表，生成新的对象列表。
迭代属性名称列表以生成动态对象。

＆＃13;

const bigList = [
  ['John', 1, 2],
  ['Doe', 5, 6]
];

const propertyNames = ['name', 'col1', 'col2'];

const newList = bigList.map( item => {
  const newItem = {};
  propertyNames.forEach( (propertyName, index) => {
    newItem[propertyName] = item[index];
  });
  
  return newItem;
});

console.log(newList)

＆＃13;

Answer 3

＆＃13;

let data = [["John",5,7,"something1"],
            ["David",4,2,"something2"]];
            
let newData = data.map(d => (
    {name: d[0], numbercolumn1: d[1], numbercolumn2: d[2], description: d[3]}
)) 

console.log(newData)

＆＃13;

或没有es6箭头功能：

＆＃13;

var data = [["John",5,7,"something1"],
            ["David",4,2,"something2"]];

var newData = data.map(function(d) {
  return {
    name: d[0], numbercolumn1: d[1], numbercolumn2: d[2], description: d[3]
  }
})

console.log(newData)

＆＃13;

希望这有帮助

Answer 4

使用ES6，您可以使用destructuring assignment和short hand properties作为对象。

＆＃13;

.git

＆＃13;

var data = [["John", 5, 7, "something1"], ["David", 4, 2, "something2"]],
    result = data.map(([name, numbercolumn1, numbercolumn2, description]) => ({ name, numbercolumn1, numbercolumn2, description }));

console.log(result);

＆＃13;

从2D数组创建对象数组

4 个答案: