Question

我试图通过附加内容传递一个名为热门人物的对象的数组列表。

我在对象中实现了parcelable接口

public class PopularPeople implements Parcelable {

@SerializedName("popularity")
private double popularity;

@SerializedName("name")
private String name;

@SerializedName("profile_path")
private String profilePath;

@SerializedName("id")
private int id;

@SerializedName("adult")
private boolean adult;

public void setPopularity(double popularity){
    this.popularity = popularity;
}

public double getPopularity(){
    return popularity;
}

public void setName(String name){
    this.name = name;
}

public String getName(){
    return name;
}

public void setProfilePath(String profilePath){
    this.profilePath = profilePath;
}

public String getProfilePath(){
    return profilePath;
}

public void setId(int id){
    this.id = id;
}

public int getId(){
    return id;
}

public void setAdult(boolean adult){
    this.adult = adult;
}

public boolean isAdult(){
    return adult;
}

@Override
public String toString(){
    return 
        "PopularPeople{" +
        "popularity = '" + popularity + '\'' +
        ",name = '" + name + '\'' + 
        ",profile_path = '" + profilePath + '\'' + 
        ",id = '" + id + '\'' + 
        ",adult = '" + adult + '\'' + 
        "}";
    }

@Override
public int describeContents() {
    return 0;
}

@Override
public void writeToParcel(Parcel dest, int flags) {
    dest.writeDouble(this.popularity);
    dest.writeString(this.name);
    dest.writeString(this.profilePath);
    dest.writeInt(this.id);
    dest.writeByte(this.adult ? (byte) 1 : (byte) 0);
}

public PopularPeople() {
}

protected PopularPeople(Parcel in) {
    this.popularity = in.readDouble();
    this.name = in.readString();
    this.profilePath = in.readString();
    this.id = in.readInt();
    this.adult = in.readByte() != 0;
}

public static final Parcelable.Creator<PopularPeople> CREATOR = new Parcelable.Creator<PopularPeople>() {
    @Override
    public PopularPeople createFromParcel(Parcel source) {
        return new PopularPeople(source);
    }

    @Override
    public PopularPeople[] newArray(int size) {
        return new PopularPeople[size];
    }
};
}

现在在一个活动中，我正在创建一个新的热门人物对象，并从另一个对象Cast中创建一个PopularPeople列表

        detailCastSeeAll.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            // we need to convert CAST to POPULARPEOPLE. We only need name, profile path and ID.
            ArrayList<PopularPeople> popularPeople = new ArrayList<>();
            Bundle b = new Bundle();
            for(Cast c : cast){
                PopularPeople p = new PopularPeople();
                p.setName(c.getName());
                p.setId(c.getId());
                p.setProfilePath(c.getProfilePath());
                popularPeople.add(p);
                Timber.e("Added %s",c.getName());
            }
            Timber.e("Length before  sendin list %d",popularPeople.size());
            Intent i = new Intent(MovieDetailActivity.this, PopularPeopleActivity.class);
            b.putParcelableArrayList(AppConstants.CAST_LIST,popularPeople);
            i.putExtras(b);
            i.putExtra(AppConstants.TAG,AppConstants.MOVIE_CAST);
            startActivity(i);
        }
    });

现在，当我在另一个类中收到此信息时，收到的数组列表仍为空，并且没有填充我从其他活动发送的数据列表。

           b = getIntent().getExtras();
    if (b != null){
        ArrayList<PopularPeople> peopleList = 
        b.getParcelableArrayList(AppConstants.CAST_LIST);
        tag = b != null ? b.getString(AppConstants.TAG) : null;
    }else{
        Toast.makeText(this, "Error loading. Please try again..", Toast.LENGTH_SHORT).show();
        finish();
        // return is required as we dont want to execute the code below and just want the activity to close.
        return;
    }

在我收到意图的第二个活动中，如果我注销了受欢迎的人的大小，它会给出0.如何解决这个问题？

Answer 1

您可能需要考虑将Arraylist保存到SharedPreferences并通过额外的intent传递密钥。

我觉得最容易使用Gson和json将自定义对象的Arraylist写入SharedPreferences。这是一个关于如何做到这一点的好教程：https://youtu.be/jcliHGR3CHo

但如果您想使用parcelable，我建议您观看本教程：https://youtu.be/WBbsvqSu0is

我希望这可以帮到你！

Answer 2

您可以使用＆＃34; serializable＆＃34;而不是＆＃34; parceable＆＃34 ;.

尝试这种方式可以帮助您

首先要制作

Class Venue实现Serializable

 public class Venue implements Serializable { /** * */ 
 private static final long serialVersionUID = 1L; }

在您的FirstActivity中这样做

 ArrayList<Venue> VenueArrayList = new ArrayList<Venue>(); 
 Intent intent = new Intent(this,secondActivity.class);      
 intent.putExtra("VenueArrayList", VenueArrayList);

在您的SecondActivity中这样做

 ArrayList<Venue> VenueArrayList; VenueArrayList = (ArrayList<Venue>)
  getIntent().getSerializableExtra( "VenueArrayList");

如何通过Intent发送Object的ArrayList？

2 个答案: