PHP Multiline regexp

Question

大家好我正在尝试为PHP创建一个正则表达式，这将允许我获得引用和作者。如果一切都是一行，我已经使它工作了，但是当它放在多行中它停止工作的那一刻。我究竟做错了什么？

(\[quote\])(.*)(\|)(.*)(\[\/quote\])

  

[quote]沉默在船上，沉默在街上，The Locks and   Haganport的码头会在你睡觉的时候抢劫你。| - 流行的孩子们   韵[/报价]

     沉默你睡觉。| - 流行儿童的韵[/ quote]

Answer 1

使用s modifier（如果在正则表达式分隔符后附加）。另外，通过添加.*：

让您的?非贪婪

preg_match_all("~\[quote\](.*?)\|(.*?)\[/quote\]~s", $s, $results,  PREG_SET_ORDER);

输出位于$results：

[
    [
        "[quote]Silence in the boatyard, Silence in the street, The Locks and Quays of Haganport Will rob you while you sleep.|-popular children's rhyme[/quote]",
        "Silence in the boatyard, Silence in the street, The Locks and Quays of Haganport Will rob you while you sleep.",
        "-popular children's rhyme"
    ], [
        "[quote]Silence you sleep.|-popular children's rhyme[/quote]",
        "Silence you sleep.",
        "-popular children's rhyme"
    ]
]

Answer 2

代码

See regex in use here

\[quote\](.*?)\|-(.*?)\[\/quote\]

注意：上面的正则表达式使用s修饰符。或者，您可以将.替换为[\s\S]并停用s修饰符

用法

$re = '/\[quote\](.*?)\|-(.*?)\[\/quote\]/s';
$str = '[quote]Silence in the boatyard, Silence in the street, The Locks and Quays of Haganport Will rob you while you sleep.|-popular children\'s rhyme[/quote]

[quote]Silence you sleep.|-popular children\'s rhyme[/quote]';

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

// Print the entire match result
var_dump($matches);

结果

输入

  

[quote]沉默在船上，沉默在街上，The Locks and   Haganport的码头会在你睡觉的时候抢劫你。| - 流行的孩子们   韵[/报价]

     沉默你睡觉。| - 流行儿童的韵[/ quote]

输出

以下输出按组（由换行符分隔）

组织

Silence in the boatyard, Silence in the street, The Locks and Quays of Haganport Will rob you while you sleep.
popular children's rhyme

Silence you sleep.
popular children's rhyme

说明

• \[quote\]按字面意思匹配（反斜杠转义后续字符）
• (.*?)任意次数捕获任何角色，但尽可能少捕获到捕获组1
• \|-按字面意思匹配（反斜杠转义后续字符）
• (.*?)任意次数捕获任何字符，但尽可能少捕获到捕获组2
• \[\/quote\]按字面意思匹配（反斜杠转义后续字符）