Question

我有两个列表A = ['1a', '3c']和B = ['2a', '1b']。我想补充一下字符串以相同的字符结尾并更新A的内容，如下所示：

最终结果为：A = ['3a', '3c']。以下是我的代码：

for x, y in enumerate(A):
        # gets the indices of B which has same end character
        l = [B.index(i) for i in B if y[1] in i]

Answer 1

你可以使用正则表达式从字符中拆分int，然后求和它们是否相等，使用list comp（考虑到两个列表的len是等于）：

导入重新

A = ['1a', '3c', "2b"]
B = ['2a', '1b', "4c"]

def splitNum(x):
  return list(filter(None, re.split(r'(\d+)', x)))

A = [str(int(splitNum(x)[0]) + int(splitNum(y)[0])) + (splitNum(x)[1]) for x in A for y in B if splitNum(x)[1] == splitNum(y)[1]]

print(A)

 => ['3a', '7c', '3b']

Answer 2

尝试这样的事情：

A = ['1a', '3c'] 
B = ['2a', '1b']
for i, (x, y) in enumerate(zip(A, B)):
  if x[-1] == y[-1]:
    A[i] = str(int(x[0])+int(y[0])) + x[-1]
print A

从列表python中添加类似的字母数字元素

2 个答案: