Question

我想按工资开头用嵌套数组排序获得最高工资的人以收到最低者的人结束一。我t want to take into consideration the currency... I don知道怎么做... 提前致谢

Array
(
[0]=>Array
(
[firstName]=>John
[lastName]=>Doe
[age]=>35
[salary]=>Array
(
[gbp]=>"180"
[eur]=>“”
[usd]=>""
)
)
[1]=>Array
(
[firstName]=>Maria
[lastName]=>Anders
[age]=>26
[salary]=>Array
(
[gbp]=>""
[eur]=>"100"
[usd]=>""
)
)
[2]=>Array
(
[firstName]=>Thomas
[lastName]=>Hardy
[age]=>31
[salary]=>Array
(
[gbp]=>""
[eur]=>""
[usd]=>"224"
)
)
)

Answer 1

看起来你发布了php。

无论如何，请看一下sort函数：

var numbers = [{
  age: 10,
  salary: {
    gbp: 10,
    eur: 0,
    usd: 0
  }
}, {
  age: 2,
  salary: {
    gbp: 0,
    eur: 345,
    usd: 0
  }
}, {
  age: 100,
  salary: {
    gbp: 0,
    eur: 0,
    usd: 23
  }
}, {
  age: 50,
  salary: {
    gbp: 0,
    eur: 432,
    usd: 0
  }
}];

numbers.sort(function(a, b) {
  // Get the sum of salaries in the a object
  let aAmt = Object.values(a.salary).reduce((s, v) => s + v, 0)
  // Get the sum of salaries in the b object
  let bAmt = Object.values(b.salary).reduce((s, v) => s + v, 0)
  // Calculate the difference
  return bAmt - aAmt
})

console.log(numbers);

Answer 2

我不认为你发布的是JS，但如果你在JS中有类似的数组类型，你可以尝试使用以下

假设数组看起来像这样

var x = [['John', 'Doe', 35, [180,0,0]],['Maria','Anders',26,[0,100,0]],['Thomas','Hardy',31,[0,0,224]]]

然后你可以使用这个

function sorty(a,b){
    if(Math.max.apply(null, a[3]) > Math.max.apply(null, b[3])) return -1;
    if(Math.max.apply(null, a[3]) < Math.max.apply(null, b[3])) return 1;
    return 0
}

然后运行：

x.sort(sorty)

会给你这个：

    0: (4) ["Thomas", "Hardy", 31, Array(3)]
    1: (4) ["John", "Doe", 35, Array(3)]
    2: (4) ["Maria", "Anders", 26, Array(3)]

我猜是一种黑客解决方案。

Answer 3

虽然salary对象中只有一个相关值，但您可以使用logical OR ||从中获取值以进行排序。如果没有值truthy，则采用零。

在Array#sort的回调中，取两个值的增量，a - b在a之前对较小的b进行排序。如果您想对降序进行排序，只需将操作数反转为b - a。

var array = [{ firstName: "John", lastName: "Doe", age: 35, salary: { gbp: "180", eur: "", usd: "" } }, { firstName: "Maria", lastName: "Anders", age: 26, salary: { gbp: "", eur: "100", usd: "" } }, { firstName: "Thomas", lastName: "Hardy", age: 31, salary: { gbp: "", eur: "", usd: "224" } }];

array.sort(function (a, b) {
    var aa = a.salary.gbp || a.salary.eur || a.salary.usd || 0,
        bb = b.salary.gbp || b.salary.eur || b.salary.usd || 0;

    return bb - aa;
});

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

如何按编号对JS中的嵌套数组进行排序？

3 个答案: