我有一份附有表格的'今年'下拉列表。然后我选择其中一年,比如2016年。当我点击提交按钮时,我希望重新加载页面,而下拉列表中的值保持在2016年(之前选择的那个)。
我该怎么做?这是我的表格:
<form class="form" method="POST" id="myID" name="myName">
<label id="year" name="year">YEARS</label>
<select name="year" id="year" class="form-control">
<option value="0" selected disabled="">CHOOSE YEAR</option>
<?php foreach($year as $rows){?>
<option value="<?php echo $rows->years?>"><?php echo $rows->years?>
</option>
<?php }?>
</select>
<button id="filter_button" style="margin-top: 26px" name="filter_button"
type="submit" class="for btn btn-info">Show</button>
</form>
答案 0 :(得分:0)
您应该使用$_POST
中的值将所选内容设置为默认值。以下是更新后的代码:
<form class="form" method="POST" id="myID" name="myName">
<label id="year" name="year">YEARS</label>
<select name="year" id="year" class="form-control">
<option value="0" selected disabled="">CHOOSE YEAR</option>
<?php foreach($year as $rows){
$isSelected = (isset($_POST['year']) && ($_POST['year'] == $rows->years)) ? 'selected' : '';
?>
<option <?php echo $isSelected; ?> value="<?php echo $rows->years?>"><?php echo $rows->years?>
</option>
<?php }?>
</select>
<button id="filter_button" style="margin-top: 26px" name="filter_button"
type="submit" class="for btn btn-info">Show</button>
</form>