Question

这是提示

编写一个读取名称并根据名称输出ID的程序。 ID应为大写，并使用名称的前三个字母和从005开始的三个数字进行格式化。如果ID已存在，则数字应增加5。

这是我目前的代码

import java.util.Scanner;

public class substring_match {

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner scan = new Scanner(System.in);
    int id = 5;
    int repeatId = 5;
    int nameCount = 1;
    String[] nameArray = new String[5];
    String name;
    String subName = null;

    for (int i = 0; i<nameArray.length; i++){
        name = scan.nextLine();
        subName = name.substring(0, 3);
        nameArray[i] = subName;
    }

    for(int x = 0; x < nameArray.length; x++){
        if(nameArray[x].substring(0, 3) == subName.substring(0,3)){
            nameCount = nameCount + 1;
            System.out.println("nameCount " + nameCount);
            repeatId = nameCount * id;
            if(repeatId == 5){
                System.out.println(nameArray[x].toUpperCase() + "00" + repeatId);
            }else{ // if repeatId is 10 or higher, won't need the extra 0
                System.out.println(nameArray[x].toUpperCase() + "0" + repeatId);
            }
        }else{
            System.out.println(nameArray[x].substring(0, 3).toUpperCase() + "00" + id);
        }
    }

}

}

Answer 1

我可能会考虑采取另一种方式......

Have an empty hashmap<String sub, int multiplier>
Read in the name
Generate the subname
Fetch from or create subname in hashmap
  If new, set multiplier to 1
  If exists, increment multiplier
Return String.format(“%s%3d”, subname, multiplier x 5).toUpperCase()

我会给你代码，但在iPad上写上面的内容很难

跟踪字符串匹配以创建新ID

1 个答案: