我遇到了将fetchall返回作为正确数据类型的问题。 fetchone有用吗?!?!
con = sqlite3.connect('test.db', detect_types=sqlite3.PARSE_DECLTYPES)
与con:
cur = con.cursor()
cur.execute("SELECT df1 FROM PLCValues")
rows = cur.fetchall()
#print(rows)
for row in rows:
print (row)
print(row)
返回
================= RESTART: C:/Users/zippo/Desktop/Graphit.py =================
(44.64769744873047,)
(44.691650390625,)
(44.691650390625,)
(44.471900939941406,)
(44.64769744873047,)
FETCHONE
con = sqlite3.connect('test.db', detect_types=sqlite3.PARSE_DECLTYPES)
与con:
cur = con.cursor()
cur.execute("SELECT df1 FROM PLCValues")
rows = cur.fetchone()
#print(rows)
for row in rows:
print (row)
print(row)
返回:
================= RESTART: C:/Users/zippo/Desktop/Graphit.py =================
44.64769744873047
44.64769744873047
答案 0 :(得分:2)
cur.fetchall()
返回一个元组元组。根据{{3}},它似乎正在返回正确的类型。您可能希望迭代单个元组以获得单个元素。