Question

我想拆分一个主字符串，并用Ruby中的单词创建多个字符串。

str = "one two three four five"

我想在一个字符串数组中创建所有这些可能性：

"one"
"one two"
"one two three"
"one two three four" 
"one two three four five"

但也是：

"two three four five"
"three four five"
"four five"
"five"

理想情况下，我也会在里面获得字符串，但不是必需的：

"two three four"
"two three"
"three four"

我尝试了很多东西，但很难有最好的方法来做到这一点。

例如，我尝试使用each_slice：

words = string.split(" ")
        number_of_words = words.length
        max_number_of_slices = number_of_words
        array_of_strings_to_match = []
        number_of_slices = 1
        while (number_of_slices <= max_number_of_slices)
          array = words.each_slice(number_of_slices).map do |a| a.join ' ' end
          array.each do |w| array_of_strings_to_match << w end
          number_of_slices = number_of_slices + 1
        end

但这不是好方法。

欢迎任何想法。： - ）

这个问题与this one略有不同，因为我需要分割一个单词的句子，而不是一个字母的字符串（即使它完全相同）。

Answer 1

str = "one two three four five".split
1.upto(str.size).flat_map { |i| str.each_cons(i).to_a }

#⇒ [["one"], ["two"], ["three"], ["four"], ["five"],
#   ["one", "two"], ["two", "three"], ["three", "four"], ["four", "five"],
#   ["one", "two", "three"], ["two", "three", "four"], ["three", "four", "five"],
#   ["one", "two", "three", "four"], ["two", "three", "four", "five"], 
#   ["one", "two", "three", "four", "five"]]

Answer 2

基于this answer的修改版本：

def split_words(string)
  words = string.split
  (0..words.length).inject([]) do |ai,i|
    (1..words.length - i).inject(ai) { |aj,j| aj << words[i,j] }
  end.map { |words| words.join(' ') }.uniq
end

用法

str = "one two three four five"

split_words(str)
#=> ["one",
#    "one two",
#    "one two three",
#    "one two three four",
#    "one two three four five",
#    "two",
#    "two three",
#    "two three four",
#    "two three four five",
#    "three",
#    "three four",
#    "three four five",
#    "four",
#    "four five",
#    "five"]

如何在Ruby中将句子分成多个部分

2 个答案: