我必须在我的应用程序的各种堆栈中使用AWS lambda,因此我创建了一个通用的云形成模板来创建lambda函数。此模板可以包含在另一个云形成模板中,以便进一步用作nested stack。
# Basics
AWSTemplateFormatVersion: '2010-09-09'
Description: AWS CloudFormation Template to create a lambda function for java 8 or nodejs
# Parameters
Parameters:
FunctionName:
Type: String
Description: Funciton Name
HandlerName:
Type: String
Description: Handler Name
FunctionCodeS3Bucket:
Type: String
Description: Name of s3 bucket where the function code is present
Default: my-deployment-bucket
FunctionCodeS3Key:
Type: String
Description: Function code present in s3 bucket
MemorySize:
Type: Number
Description: Memory size between 128 MB - 1536 MB and multiple of 64
MinValue: '128'
MaxValue: '1536'
Default: '128'
RoleARN:
Type: String
Description: Role ARN for this function
Runtime:
Type: String
Description: Runtime Environment name e.g nodejs, java8
AllowedPattern: ^(nodejs6.10|nodejs4.3|java8)$
ConstraintDescription: must be a valid environment (nodejs6.10|nodejs4.3|java8) name.
Timeout:
Type: Number
Description: Timeout in seconds
Default: '3'
Env1:
Type: String
Description: Environment Variable with format Key|value
Default: ''
Env2:
Type: String
Description: Environment Variable with format Key|value
Default: ''
Env3:
Type: String
Description: Environment Variable with format Key|value
Default: ''
Env4:
Type: String
Description: Environment Variable with format Key|value
Default: ''
# Conditions
Conditions:
Env1Exist: !Not [ !Equals [!Ref Env1, '']]
Env2Exist: !Not [ !Equals [!Ref Env2, '']]
Env3Exist: !Not [ !Equals [!Ref Env3, '']]
Env4Exist: !Not [ !Equals [!Ref Env4, '']]
# Resources
Resources:
LambdaFunction:
Type: AWS::Lambda::Function
Properties:
Code:
S3Bucket: !Ref 'FunctionCodeS3Bucket'
S3Key: !Ref 'FunctionCodeS3Key'
Description: !Sub 'Lambda function for: ${FunctionName}'
Environment:
Variables:
'Fn::If':
- Env1Exist
-
- !Select [0, !Split ["|", !Ref Env1]]: !Select [1, !Split ["|", !Ref Env1]]
- 'Fn::If':
- Env2Exist
- !Select [0, !Split ["|", !Ref Env2]]: !Select [1, !Split ["|", !Ref Env2]]
- !Ref "AWS::NoValue"
- 'Fn::If':
- Env3Exist
- !Select [0, !Split ["|", !Ref Env3]]: !Select [1, !Split ["|", !Ref Env3]]
- !Ref "AWS::NoValue"
- 'Fn::If':
- Env4Exist
- !Select [0, !Split ["|", !Ref Env4]]: !Select [1, !Split ["|", !Ref Env4]]
- !Ref "AWS::NoValue"
- !Ref "AWS::NoValue"
FunctionName: !Ref 'FunctionName'
Handler: !Ref 'HandlerName'
MemorySize: !Ref 'MemorySize'
Role: !Ref 'RoleARN'
Runtime: !Ref 'Runtime'
Timeout: !Ref 'Timeout'
Outputs:
LambdaFunctionARN:
Value: !GetAtt 'LambdaFunction.Arn'
我想将环境变量注入到函数中,并将从父堆栈传递,如下所示:
# Resouces
Resources:
# Lambda for search Function
ChildStackLambdaFunction:
Type: AWS::CloudFormation::Stack
Properties:
TemplateURL: <<REF_TO_ABOVE_LAMBDA_STACK.yml>>
Parameters:
FunctionName: test
HandlerName: 'index.handler'
FunctionCodeS3Bucket: <<BUCKET_NAME>>
FunctionCodeS3Key: <<FUNCTION_DEPLOYMENT_NAME>>
MemorySize: '256'
RoleARN: <<ROLE_ARN>>
Runtime: nodejs6.10
Timeout: '60'
Env1: !Sub 'AWS_REGION|${AWS::Region}'
当我部署此堆栈时,我遇到了错误。有人可以帮我解决这个问题吗?
模板格式错误:[/ Resources / LambdaFunction / Type / Environment / Variables / Fn :: If / 1/0] map键必须是字符串;收到地图
传递键值参数来自here
答案 0 :(得分:7)
所以,我尝试了很多方法来实现这一点,但我们无法将动态键值对从父堆栈传递给嵌套的lambda堆栈。我从AWS支持部门得到了一个确认,认为这是不可能的。
他们提出了另一种我喜欢和实施的方式,如下所述:
将key:value对作为JSON字符串传递,并在lambda函数中适当地解析它。
Environment:
Variables:
Env1: '{"REGION": "REGION_VALUE", "ENDPOINT": "http://SOME_ENDPOINT"}'
这个建议在解析JSON字符串的编程上有一点开销,但此时我会建议将其作为上述问题的解决方案。
答案 1 :(得分:0)
我通过PyPlate宏实现了这一目标。 将环境变量列表以逗号分隔
Parameters:
EnvVars:
Type: CommaDelimitedList
Description: Comma separated list of Env vars key=value pairs (key1=value1,key2=value2)
并在Lambda资源中使用它:
Environment:
Variables: |
#!PyPlate
output = dict()
for envVar in params['EnvVars']:
key, value = envVar.split('=')
output.update({key: value})