Question

我有一个很小的PHP代码，它读出一个包含y或n或b的文件。我已经回显了文件输出，它显示完美y。现在，如果我将变量与y进行比较，它就不接受它并继续使用else。

$result = mysqli_query($db, "SELECT ID FROM review WHERE reviewer_ID='$reviewer_ID' AND products_ID='$products_ID'");
            if ($result->num_rows > 0){ 
            // this person has already reviewed it
            echo "you have already reviewed it<br />";
            echo "<p><a href=\"../page.php?productid=". $F_products_ID ."\">Zurück</a></p>";
    }else{

    // $out= y if its valid and $out= n if its a invalid review
    $out = shell_exec ("/home/script.sh $reviewlink");
    // time for the script to run. needs aprx. 1-2 seconds.
    sleep(2);
    // variables for PHP
    $valid = file_get_contents('/home/script/valid');
    $digits = file_get_contents('/home/script/digits');
    // PHP sends it to the DB if true

        if ($out == 'b' or $valid == 'b'){
        echo "<p>We have an issue right now!</a></p>";
        header('location:issue.php?productid=$F_products_ID');
        } else {
        echo "Review Status from file: $valid <br>";
        echo "Review Status from script: $out <br>";
        echo "Digits in Review: $digits <br><br>";
        if (($out == 'y' or $valid == 'y') and $digits >= $mindigits){
        //do stuff

所以回声和有效显示y和数字正确，但将它们与y（或与心灵）进行比较似乎不起作用。 PHP认为y = / y而我得不到它......

Answer 1

尝试将[0]添加到变量中：

if ($out[0] == 'y' or $valid[0] == 'y'){ ... }

因此，只有第一个字符用于比较过程。

php比较变量不起作用

1 个答案: