Question

我在docker容器中运行nginx。我希望有一个子目录/web/来访问我的个人文件和项目。它也应该支持php。

以下是我正在运行但domain-a.com/web继续生成404.由于相同的php块在子域上工作但直接在server{}块中，因此确认PHP正常工作。

http {

    server {
        listen      443 ssl;
        server_name domain-a.com domain-b.com;

        # Mime types
        include /etc/nginx/confs/mime.types;

        # SSL
        include /etc/nginx/confs/nginx-ssl.conf;

        # Proxy to organizr
        # This works
        location / {
            proxy_pass http://organizr/;
            proxy_set_header Host $http_host;
            proxy_set_header X-Real-IP $remote_addr;
            proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for;
            proxy_set_header X-Forwarded-Proto $scheme;

            # HTTP 1.1 support
            proxy_http_version 1.1;
            proxy_set_header Connection "";
        }

        # Root folder for my personal files/projects
        # Doesn't work
        location /web {
            index index.php index.html;
            root /etc/nginx/www;

            location ~ \.php$ {
                try_files $uri =404;
                fastcgi_split_path_info ^(.+\.php)(/.+)$;
                fastcgi_pass php:9000;
                fastcgi_index index.php;
                include fastcgi_params;
                fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
                fastcgi_param PATH_INFO $fastcgi_path_info;
            }
        }
    }
}

Answer 1

如果您的文件位于/etc/nginx/www，则需要使用alias指令，而不是root指令。有关详细信息，请参阅this document。

例如：

location ^~ /web {
    index index.php index.html;
    alias /etc/nginx/www;

    if (!-e $request_filename) { rewrite ^ /web/index.php last; }

    location ~ \.php$ {
        if (!-f $request_filename) { return 404; }

        fastcgi_pass php:9000;
        include fastcgi_params;
        fastcgi_param SCRIPT_FILENAME $request_filename;
    }
}

使用$request_filename获取别名文件的正确路径。由于this issue，try_files与alias一起避免if。有关使用let MainStory: UIStoryboard = UIStoryboard(name: "Main", bundle: nil) let desVC = MainStory.instantiateViewController(withIdentifier: "FourthViewController") as! FourthViewController的信息，请参阅this caution。

使用PHP的Nginx子目录根

1 个答案: