let dictionaryToJsonObject: [String: Any]
let Dictionary: [String: Any] = ["FirstName": "John", "Email": "Jo@sm.com", "Password": "john@123", "LastName": "Smith", "Organization": ["Type": 5, "Name": "IT"]]
do {
let jsonData = try JSONSerialization.data(withJSONObject: Dictionary as Any, options: .prettyPrinted)
let jsonText = String(data: jsonData,
encoding: .ascii)
print("JSON string = \(jsonText!)")
if JSONSerialization.isValidJSONObject(jsonText!) {
print("Valid")
} else {
print("Not Valid")
}
}catch {
print(error.localizedDescription)
}
输出将是: -
JSON string = {
"FirstName" : "John",
"Email" : "Jo@sm.com",
"Password" : "john@123",
"LastName" : "Smith",
"Organization" : {
"Type" : 5,
"Name" : "IT"
}
}
预期结果:
{
FirstName:"John",
Email:"Jo@sm.com",
Password:"john@123",
LastName:"Smith",
Organization:{
Type:5,
Name:"IT"
}
}
答案 0 :(得分:0)
如果你想以json对象形式获取它,那么你的代码应该是,
let dictionaryToJsonObject: [String: Any]
let Dictionary: [String: Any] = ["FirstName": "John", "Email": "Jo@sm.com", "Password": "john@123", "LastName": "Smith", "Organization": ["Type": 5, "Name": "IT"]]
do {
let jsonData = try JSONSerialization.data(withJSONObject: Dictionary as Any, options: .prettyPrinted)
let jsonObject = try JSONSerialization.jsonObject(with: jsonData, options: .init(rawValue: 0))
print("JSON string = \(jsonObject)")
if JSONSerialization.isValidJSONObject(jsonObject) {
print("Valid")
} else {
print("Not Valid")
}
}catch {
print(error.localizedDescription)
}
,你的输出将是,
JSON string = {
Email = "Jo@sm.com";
FirstName = John;
LastName = Smith;
Organization = {
Name = IT;
Type = 5;
};
Password = "john@123";
}
Valid
最终,我认为这是你宣布的词典本身!