我在listproduct.ts
if (val && val.trim() != '') {
this.names = this.names.filter((names) => {
return (names.toLowerCase().indexOf(val.toLowerCase()) > -1);
})
}
请注意,此过滤器适用于names
阵列。我希望此过滤器也适用于catg
和pservice
命名数组。
如何在多个阵列上实现过滤结果。
请指导。
答案 0 :(得分:0)
您可以使用js concat函数创建另一个bigArray
,这是三个数组的串联:
var bigArray = this.names.concat(this.catg, this.pservice);
并在bigArray
上调用您的过滤器。
var val = "test";
this.names = ["abc", "test123", "test"];
this.catg = ["qsd", "azetest"];
this.pservice = ["another test !", "tss"];
this.bigArray = this.names.concat(this.catg, this.pservice);
// here, bigArray contains all values of the three arrays (abc,test123,test,qsd,azetest,another test !,tss)
if (val && val.trim() != '') {
this.bigArray = this.bigArray.filter((names) => {
return (names.toLowerCase().indexOf(val.toLowerCase()) > -1);
})
// here, bigArray contains only filtered values of the three arrays (test123,test,azetest,another test !)
这是一个有效的Plunker
答案 1 :(得分:0)
如果你需要将它们作为单独的数组保存,并且无法连接它们,你可以这样做:
let names = ["Andy", "Alex", "Corbyn", "Eric" ];
let catg = ["Adventure", "Action", "Comedy", "SciFi"];
let pservice = ["Example", "Service", "Allo"]
let val = "a";
[names, catg, pservice] = [names, catg, pservice].map(array => {
return array.filter((item) => {
return (item.toLowerCase().indexOf(val.toLowerCase()) > -1);
})
});
console.log(names);
console.log(catg);
console.log(pservice);