Question

如果差异大于35天，如何计算两个日期之间的约会？

这是我的疑问：

SELECT CONCAT(IF('2017-08-01 10:00:00' < NOW(), '-', ''), FLOOR(HOUR(TIMEDIFF(NOW(), '2017-08-01 10:00:00')) / 24), ' days ',
MOD(HOUR(TIMEDIFF(NOW(),'2017-08-01 10:00:00')), 24), ' hours ', MINUTE(TIMEDIFF(NOW(),'2017-08-01 10:00:00')), ' minutes') AS TimeLeft

但它显示错误的计算。

+------------------------------+
| TimeLeft                     |
+------------------------------+
| -34 days 22 hours 59 minutes |
+------------------------------+

应该至少有100天的差异。

Answer 1

https://dev.mysql.com/doc/refman/5.7/en/date-and-time-functions.html#function_timediff说：

TIMEDIFF（）返回的结果仅限于TIME值允许的范围。

https://dev.mysql.com/doc/refman/5.7/en/time.html说：

TIME值的范围可以是＆＃39; -838：59：59＆＃39;到＆＃39; 838：59：59＆＃39;

然后我们意识到

FLOOR(838 hours / 24 hours) = 34

这是另一种有效的方法（至少到2038年）：

mysql> select concat(
  ceil(tdiff/24/60/60), ' days, ',
  floor(mod(abs(tdiff)/60/60, 24)), ' hours, ',
  floor(mod(abs(tdiff)/60, 60)), ' minutes') as t
from (select unix_timestamp('2017-08-01 10:00:00') - unix_timestamp(now()) as tdiff) as t;
+---------------------------------+
| t                               |
+---------------------------------+
| -100 days, 13 hours, 10 minutes |
+---------------------------------+

这是另一个想法：

mysql> select to_days('1970-01-01')-to_days(td) as days, time(td) as hhmmss
 from (select from_unixtime(abs(unix_timestamp('2017-08-01 10:00:00') - unix_timestamp(now()))); 
+------+----------+
| days | hhmmss   |
+------+----------+
| -100 | 13:18:12 |
+------+----------+

MySQL计算日期差异大于35天

1 个答案: