我很难将if
语句转换为不同的方法。我试图将它转换为4个单独的方法:add,sub,mul和div,它必须在CMD中声明,但我不能以某种方式做到。我需要帮助和谢谢。
public static void main(String[] args){
int first = Integer.parseInt(args[1]);
int second = Integer.parseInt(args[2]);
int third = Integer.parseInt(args[3]);
int forth = Integer.parseInt(args[4]);
if(args[0].equals("add")){
if (second == 0 || forth == 0){
System.out.println("Undividable by zero");
} else if (second == forth){
System.out.println(first + "/" + second + " + " + third + "/" + forth + " = " + (first + third) + "/" + forth);
} else {
System.out.println(first + "/" + second + " + " + third + "/" + forth + " = " + (first * forth + second * third) + "/" + (second * forth));
}
} else if (args[0].equals("sub")){
if (second == 0 || forth == 0){
System.out.println("Undividable by zero");
} else if (second == forth){
System.out.println(first + "/" + second + " - " + third + "/" + forth + " = " + (first + third) + "/" + forth);
} else {
System.out.println(first + "/" + second + " - " + third + "/" + forth + " = " + (first * forth - second * third) + "/" + (second * forth));
}
} else if (args[0].equals("mul")){
if (second == 0 || forth == 0){
System.out.println("Undividable by zero");
} else {
System.out.println(first + "/" + second + " * " + third + "/" + forth + " = " + (first * third ) + "/" + (second * forth));
}
} else if (args[0].equals("div")){
if (second == 0 || forth == 0){
System.out.println("Undividable by zero");
} else {
System.out.println(first + "/" + second + " : " + third + "/" + forth + " = " + (first * forth) + "/" + (second * third));
}
} else {
System.out.println("Recheck the code");
}
}
答案 0 :(得分:0)
或者如果你想制作一种方法 public void this_is_your_method(int n){...}
我假设你遇到的问题是因为System.out.println,在制作方法时你需要说明你想要返回的是什么类型,因为你想打印一些你会说无效的东西。你不想打印任何东西只是打印这个并且我写了int以使你的工作更容易,因为写一次所有代码比多次更好只需将args [0]更改为args [n]
答案 1 :(得分:0)
示例强>
<强> Main.Class 强>
public static void main(String[] args) {
int first = Integer.parseInt(args[1]);
int second = Integer.parseInt(args[2]);
int third = Integer.parseInt(args[3]);
int forth = Integer.parseInt(args[4]);
if(args[0].equals("add")){
add(first,second,third,forth);
} ...
}
public static void add(int first, int second, int third, int forth) {
if (second == 0 || forth == 0){
System.out.println("Undividable by zero");
} else if (second == forth){
System.out.println(first + "/" + second + " + " + third + "/" + forth + " = " + (first + third) + "/" + forth);
} else {
System.out.println(first + "/" + second + " + " + third + "/" + forth + " = " + (first * forth + second * third) + "/" + (second * forth));
}
}
答案 2 :(得分:0)
当有很多if then else时你也可以选择switch-case。
以下是如何将代码模块化为方法...
我也在分享如何使用lambda函数(java 8)。
interface MathOperation {
public void operate(int first, int second, int third, int forth);
}
public class StackOverflow {
public static void main(String[] args) {
int first = Integer.parseInt(args[1]);
int second = Integer.parseInt(args[2]);
int third = Integer.parseInt(args[3]);
int forth = Integer.parseInt(args[4]);
MathOperation addition = (a, b, c, d) -> { if (b == 0 || d == 0) System.out.println("Undividable by zero"); else if (b == d) System.out.println(a + "/" + b + " + " + c + "/" + d + " = " + (a + c) + "/" + d); else System.out.println(a + "/" + b + " + " + c + "/" + d + " = " + (a * d + b * c) + "/" + (b * d));};
MathOperation subtraction = (a, b, c, d) -> { if (b == 0 || d == 0) System.out.println("Undividable by zero"); else if (b == d) System.out.println(a + "/" + b + " - " + c + "/" + d + " = " + (a + c) + "/" + d); else System.out.println(a + "/" + b + " - " + c + "/" + d + " = " + (a * d - b * c) + "/" + (b * d));};
MathOperation multiplication = (a, b, c, d) -> { if (b == 0 || d == 0) System.out.println("Undividable by zero"); else System.out.println(a + "/" + b + " * " + c + "/" + d + " = " + (a * c) + "/" + (b * d));};
MathOperation division = (a, b, c, d) -> { if (b == 0 || d == 0) System.out.println("Undividable by zero"); else System.out.println(a + "/" + b + " : " + c + "/" + d + " = " + (a * d) + "/" + (b * c));};
switch(args[0]) {
case "add" :
add(first, second, third, forth);
addition.operate(first, second, third, forth);
break;
case "sub":
sub(first, second, third, forth);
subtraction.operate(first, second, third, forth);
break;
case "div":
div(first, second, third, forth);
division.operate(first, second, third, forth);
break;
case "mul":
multiply(first, second, third, forth);
multiplication.operate(first, second, third, forth);
break;
default :
System.out.println("Recheck the code");
}
}
private static void multiply(int first, int second, int third, int forth) {
if (second == 0 || forth == 0) {
System.out.println("Undividable by zero");
} else {
System.out.println(first + "/" + second + " * " + third + "/" + forth + " = " + (first * third) + "/"
+ (second * forth));
}
}
private static void div(int first, int second, int third, int forth) {
if (second == 0 || forth == 0) {
System.out.println("Undividable by zero");
} else {
System.out.println(first + "/" + second + " : " + third + "/" + forth + " = " + (first * forth) + "/"
+ (second * third));
}
}
private static void sub(int first, int second, int third, int forth) {
if (second == 0 || forth == 0) {
System.out.println("Undividable by zero");
} else if (second == forth) {
System.out.println(
first + "/" + second + " - " + third + "/" + forth + " = " + (first + third) + "/" + forth);
} else {
System.out.println(first + "/" + second + " - " + third + "/" + forth + " = "
+ (first * forth - second * third) + "/" + (second * forth));
}
}
private static void add(int first, int second, int third, int forth) {
if (second == 0 || forth == 0) {
System.out.println("Undividable by zero");
} else if (second == forth) {
System.out.println(
first + "/" + second + " + " + third + "/" + forth + " = " + (first + third) + "/" + forth);
} else {
System.out.println(first + "/" + second + " + " + third + "/" + forth + " = "
+ (first * forth + second * third) + "/" + (second * forth));
}
}
}