我正在制作一部具有音乐跳过功能的不和谐机器人,但我无法弄清楚如何让某人无法投票多次跳过。到目前为止,这是我的代码:
case "skip":
var server = servers[message.guild.id];
if(message.guild.members.get(message.author.id).roles.exists('name','Super Skip')){ // checks if the member has the super skip role
skipvotes = 0; // sets skipvotes back to 0
messagesend("Skipping Song")
server.dispatcher.end(); // skips song
message.delete(); // deletes message that sent the commmand
return;
}
skipvotes++ // increases the skipvotes
if(skipvotes != 5) { // checks if the number of skips is 5 or not
message.delete();
messagesend(5-skipvotes + " more vote(s) to skip the song") // sends the message saying how many more votes to skip the song
} else if(skipvotes === 5){
skipvotes = 0; // sets the number of skipvotes back to 0
if(server.dispatcher){
message.delete();
messagesend("Skipping song")
server.dispatcher.end(); // skips the song
}
}
break;
如果你们能帮助我,那就太棒了
答案 0 :(得分:2)
存储已投票的人的ID。对于每次投票,检查数组中是否已存在该ID,如果存在,则忽略该投票。
您需要在范围内声明数组,该范围将在http请求之外保留。 (我假设这是服务器代码,我不熟悉discord机器人的工作方式)可能不值得将它存储在数据库中。
var voters = []
将整数计数器替换为数组的长度。
case "skip":
var server = servers[message.guild.id];
if(message.guild.members.get(message.author.id).roles.exists('name','Super Skip')){ // checks if the member has the super skip role
voters = []
messagesend("Skipping Song")
server.dispatcher.end(); // skips song
message.delete(); // deletes message that sent the commmand
return;
}
if(voters.find(id=>id == message.author.id))
return;
voters.push(message.author.id)
if(voters.length != 5) { // checks if the number of skips is 5 or not
message.delete();
messagesend(5-voters.length + " more vote(s) to skip the song") // sends the message saying how many more votes to skip the song
} else if(voters.length === 5){
voters = []
if(server.dispatcher){
message.delete();
messagesend("Skipping song")
server.dispatcher.end(); // skips the song
}
}
break;