Question

我已经定义了一个名为LogicalNode的类，它可以用来形成一个树。我想显示整个树，但我不知道如何设置每个节点的位置。在程序中，我可以在父节点下插入一个树节点，所以当我插入一些节点时，它会导致节点之间的冲突。这是我的班级：

public class LogicalNode implements Serializable{
private String text;
private String logicalType;
private LogicalNode parent;
private LinkedList<LogicalNode> sons = new LinkedList<>();
private List<LogicalNode> tmpNodes = new ArrayList<>();

public LogicalNode(){}

public LogicalNode(String text,String logicalType,LogicalNode parent){
    this.text = text;
    this.logicalType = logicalType;
    this.parent = parent;
}

public void addSon(LogicalNode node){
    this.sons.offer(node);
    this.tmpNodes.add(node);
}

public int getOrder(){
    LogicalNode parent = this.getParent();
    if(parent == null){
        return 0;
    }else{
        return parent.getSons().indexOf(this);
    }
}

public int getLevel(){
    LogicalNode node = this;
    int level = 0;
    while(node.getParent() != null){
        node = node.getParent();
        level++;
    }
    return level;
}

@Override
public String toString() {
    return this.text;
}

public String getText() {
    return text;
}

public void setText(String text) {
    this.text = text;
}

public String getLogicalType() {
    return logicalType;
}

public void setLogicalType(String logicalType) {
    this.logicalType = logicalType;
}

public LogicalNode getParent() {
    return parent;
}

public void setParent(LogicalNode parent) {
    this.parent = parent;
}

public LinkedList<LogicalNode> getSons() {
    return sons;
}

public void setSons(LinkedList<LogicalNode> sons) {
    this.sons = sons;
}

public List<LogicalNode> getTmpNodes() {
    return tmpNodes;
}

public void setTmpNodes(List<LogicalNode> tmpNodes) {
    this.tmpNodes = tmpNodes;
}

}

此类可以用作某些GUI组件的用户Object来显示它，例如JGraphX中的mxCell。

如何重定位树节点以避免GUI中的冲突

0 个答案: