Question

这是我的数据

date           amount
2017-07-10     15.00
2017-07-10     15.00
2017-07-28     25.00
2017-08-01     100.00
2017-08-12     15.00
2017-08-29     200.00
2017-09-18     105.00
2017-09-21     200.00
2017-09-23     25.00
2017-10-12     15.00
2017-10-14     500.00
2017-11-01     200.00
2017-11-02     200.00

我希望按月添加它，所以我们将在6月得到的总数为55，8月我将得到315，9月330，10月515，11月400和过去的日期没有数量将是0如何我会这样做吗？

这是我的临时表格代码：

create table #TempTable
    (month varchar(50),
    amount decimal(18,2))


insert into #TempTable (month)
SELECT TOP 12
DATENAME(MONTH, DATEADD(MONTH,ROW_NUMBER() OVER (ORDER BY object_id) - 1,0))
FROM sys.columns

create table #Data
    (date date,
    amount decimal(18,2))
  insert into #Data(date,amount) values('2017-07-10',15.00)
  insert into #Data(date,amount) values('2017-07-10',15.00)
  insert into #Data(date,amount) values('2017-07-28',25.00)
  insert into #Data(date,amount) values('2017-08-01',100.00)
  insert into #Data(date,amount) values('2017-08-12',15.00)
  insert into #Data(date,amount) values('2017-08-29',200.00)
  insert into #Data(date,amount) values('2017-09-18',105.00)
  insert into #Data(date,amount) values('2017-09-21',200.00)
  insert into #Data(date,amount) values('2017-09-23',25.00)
  insert into #Data(date,amount) values('2017-10-12',15.00)
  insert into #Data(date,amount) values('2017-10-14',500.00)
  insert into #Data(date,amount) values('2017-11-01',200.00)
  insert into #Data(date,amount) values('2017-11-02',200.00)

  select * from #Data
  select * from #TempTable
drop table #TempTable
drop table #Data

PS。只需更新#TempTable并将总数放在上面谢谢：）

Answer 1

  SELECT a.Month,SUM(ISNULL(b.Amount,0)) 
  FROM  #TempTable a
  LEFT JOIN #Data b
  ON a.Month = DATENAME(MONTH,date)
  GROUP BY a.Month

更新

   UPDATE a
  SET Amount = ISNULL(GroupSuma,0)
  FROM  #TempTable a
  LEFT JOIN
  (
      select DATENAME(MONTH,date) as month, SUM(b.Amount) as GroupSuma
      FROM #Data b
      GROUP BY DATENAME(MONTH,date)
  ) as c
  ON a.Month = c.Month

Answer 2

使用以下代码：

SELECT Res1.[Month]
         ,ISNULL(Res2.Amount,0)
  FROM #TempTable Res1
  LEFT JOIN
  (
  select DATENAME(MONTH,Res1.date) AS [Month]
         ,SUM(amount) AS Amount 
  from #Data Res1
  GROUP BY DATENAME(MONTH,Res1.date) 
  )Res2 ON Res2.[Month] = Res1.[Month]

Answer 3

从数据表

更新temptable

update #TempTable
set amount = d.amount from ( select  datename(month, date) date
                                     , SUM(amount) amount from #Data
                                     group by datename(month, date)
                                     ) d inner join #TempTable t on t.month = d.date

                                     select * from #TempTable

Answer 4

您的一个要求是：

过去的日期没有金额将为0

您的数据集并未包含此内容，因此我在下面的示例代码中添加了两行。我还添加了一个不同的年份来说明不同年份会发生什么。 I UNION所有来自#data的值，CTE选择年份，每月＃年份和0.当SUM＆＃39; ed，0个条目中的大部分被删除，但是#Data中没有值的年份中的几个月仍然存在当量= 0时，该结果被删除，以消除#data中最小和最大日期范围之外的0行。

create table #Data (date date, amount decimal(18,2))
insert into #Data(date,amount) values('2017-07-10',15.00)
insert into #Data(date,amount) values('2017-07-10',15.00)
insert into #Data(date,amount) values('2017-07-28',25.00)
insert into #Data(date,amount) values('2017-08-01',100.00)
insert into #Data(date,amount) values('2017-08-12',15.00)
insert into #Data(date,amount) values('2017-08-29',200.00)
insert into #Data(date,amount) values('2017-09-18',105.00)
insert into #Data(date,amount) values('2017-09-21',200.00)
insert into #Data(date,amount) values('2017-09-23',25.00)
insert into #Data(date,amount) values('2017-10-12',15.00)
insert into #Data(date,amount) values('2017-10-14',500.00)
insert into #Data(date,amount) values('2017-11-01',200.00)
insert into #Data(date,amount) values('2017-11-02',200.00)

--additional test values
insert into #Data(date,amount) values('2017-05-04',5.00)
insert into #Data(date,amount) values('2018-02-22',1.00)

DECLARE @minYear int =  (SELECT YEAR(MIN(date)) FROM #data)
       ,@minMonth int =  (SELECT MONTH(MIN(date)) FROM #data)
       ,@maxYear int =  (SELECT MAX(YEAR(date)) FROM #data)
       ,@maxMonth int =  (SELECT MONTH(MAX(date)) FROM #data);

WITH cteYear AS 
(
  SELECT @minYear AS num
  UNION ALL
  SELECT num + 1 FROM cteYear WHERE num + 1 <= @maxYear
)

SELECT dT.dateyear
      ,DateName( month , DateAdd( month , dT.datemonth, -1 ) ) AS [month]
      ,SUM(dT.amount) AS [Sum Amount]
  FROM (
         SELECT YEAR(date) AS [dateyear], MONTH(date) AS [datemonth], amount -- AS [SumAmount]     
           FROM #Data D       

         UNION ALL

         SELECT num, monthlist.month, 0 
           FROM cteYear CROSS JOIN (SELECT 1 AS [month] UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4  UNION ALL 
                                    SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL 
                                    SELECT 9 UNION ALL SELECT 10 UNION ALL SELECT 11 UNION ALL SELECT 12
                                   ) AS monthlist
       ) AS dT
WHERE (@minYear <> @maxYear AND dateyear = @minYear AND datemonth >= @minMonth)
      OR
      (@minYear <> @maxYear AND dateyear = @maxYear AND datemonth <= @maxMonth)
      OR
      (@minYear <> @maxYear AND dateyear <> @minYear AND dateyear <> @maxYear)
      OR
      (@minYear = @maxYear AND datemonth >= @minMonth AND datemonth <= @maxMonth)


GROUP BY dateyear, datemonth
ORDER BY dateyear, datemonth

提供输出：

dateyear    month      Sum Amount
2017        May        5.00
2017        June       0.00
2017        July       55.00
2017        August     315.00
2017        September  330.00
2017        October    515.00
2017        November   400.00
2017        December   0.00
2018        January    0.00
2018        February   1.00

使用sql server每月添加所有金额

4 个答案: