Question

我是php的新手并且已经开始学习它了。我在php和html中有两个家庭作业。

作业1：

我必须存储一些人的姓名和所有朋友的名字。我必须只列出有共同朋友的人。我的问题是，如果一个人没有与其他人共同的朋友，我会收到一条消息“Rana和Roni有0个朋友。我会阻止这个：

作业2：

我有一个html表单来搜索上一个php文件中的人

当我搜索Rana时，PHP表单将打开并打印：

Rana有4个朋友，他和Nandini和Mamun有一个共同的朋友。
当我搜索Tanmoy时，页面将打开并打印：

Tanmoy是Rana的朋友，他与Nandini和Mamun有4个朋友和朋友。
为此，我必须使用“post / get / request”函数

到目前为止，这是我的代码：

<?php
   # Function: finfCommon

function findCommon($current, $arr) {
    $cUser = $arr[$current];
    unset($arr[$current]);
    foreach ($arr As $user => $friends) {
        $common = array();
        $total = array();
        foreach ($friends As $friend) {
            if (in_array($friend, $cUser)) {
                $common[] = $friend;
            }
        }
        $total = count($common);
        $add = ($total != 1) ? 's' : '';
        $final[] = "<i>{$current} has {$total} friend{$add} in common with {$user}.</i>";
    }
    return implode('<br />', $final);
}

# Array of users and friends

$Friends = array(
    "Rana" => array("Pothik", "Zaman", "Tanmoy", "Ishita"),
    "Nandini" => array("Bonna", "Shakib", "Kamal", "Minhaj", "Ishita"),
    "Roni" => array("Akbar", "Anwar", "Khakan", "Pavel"),
    "Liton" => array("Mahadi", "Pavel"),
    "Mamun" => array("Meheli", "Tarek", "Zaman")
);

# Creating the output value

$output = "<ul>";
foreach ($Friends As $user => $friends) {
    $total = count($friends);
    $common = findCommon($user, $Friends);
    $output .= "<li><u>{$user} has {$total} friends.</u><br /><strong>Friends:</strong>";
    if (is_array($friends) && !empty($friends[0])) {
        $output .= "<ul>";
        foreach ($friends As $friend) {
            $output .= "<li>{$friend}</li>";
        }
        $output .= "</ul>";
    }
    $output .= "{$common}<br /><br /></li>";
}
$output .= "</ul>";

# Printing the output value
print $output;
?>

Answer 1

从

更改findCommon功能

function findCommon($current, $arr) {
    $cUser = $arr[$current];
    unset($arr[$current]);
    foreach ($arr As $user => $friends) {
        $common = array();
        $total = array();
        foreach ($friends As $friend) {
            if (in_array($friend, $cUser)) {
                $common[] = $friend;
            }
        }
        $total = count($common);
        $add = ($total != 1) ? 's' : '';
        $final[] = "<i>{$current} has {$total} friend{$add} in common with {$user}.</i>";
    }
    return implode('<br />', $final);
}

到

function findCommon($current, $arr) {
    $cUser = $arr[$current];
    unset($arr[$current]);
    foreach ($arr As $user => $friends) {
        $common = array();
        $total = array();
        foreach ($friends As $friend) {
            if (in_array($friend, $cUser)) {
                $common[] = $friend;
            }
        }
        $total = count($common);
        $add = ($total != 1) ? 's' : '';
        if ( $total > 0 ) $final[] = "<i>{$current} has {$total} friend{$add} in common with {$user}.</i>";
    }
    return implode('<br />', $final);
}

我在if ( $total > 0 )

之前添加了$final[] = ..

为第二个。

<?php

function searchPerson($person, $friends){
    $direct = false;
$found = false;
    if ( in_array ($person, array_keys($friends) ) ){
        list($total, $common_friends) = commonFriend ($person, $friends);
        $direct = true;
    $found = true;
    }
    else{
        foreach ( $friends as $friend => $his_friends ){
            if ( in_array ( $person, $his_friends ) ){
                list($total, $common_friends) = commonFriend ($friend, $friends);
                $direct = false;
                    $found = true;
                $friend_person = $friend;
                break;
            }
        }
    }
    if ( !$found ) return false;
    $output = $person . " ";
    if ( $direct ){
        $output .= " has " . $total . " friends";
    }
    else{
        $output .= " is " . $friend_person . "'s friend who has " . $total . " friends"; 
    }

    if ( isset($common_friends[0]) ) $output .= " and common friends with " . $common_friends;

    return $output;
}

function commonFriend ($person, $friends){
    $my_friends = $friends[$person];
    unset($friends[$person]);
    $total_friends = count($my_friends);
    $common_with = array();

    foreach ( $friends as $friend => $his_friends ){
        foreach ( $my_friends as $my_friend ){
            if ( in_array ($my_friend, $his_friends) ){
                $common_with[] = $friend;
            }
        }
    }

    $common_with = array_unique ($common_with);

    $common_friends = "";
    if ( count($common_with) > 0 ){
        $common_friends = join (", ", $common_with );
    }

    return array ( $total_friends, $common_friends );
}

$friends = array(
    "Rana" => array("Pothik", "Zaman", "Tanmoy", "Ishita"),
    "Nandini" => array("Bonna", "Shakib", "Kamal", "Minhaj", "Ishita"),
    "Roni" => array("Akbar", "Anwar", "Khakan", "Pavel"),
    "Liton" => array("Mahadi", "Pavel"),
    "Mamun" => array("Meheli", "Tarek", "Zaman")
);


$person = $_GET['person'];

$output = searchPerson($person, $friends);

if ( $output === false ) print $person . " is not on the list";
else print $output;

?>

与第二项任务有关的是你需要一份表格。

我们可以说上面的代码名为searchPerson.php

然后添加一个像

这样的html页面

<html>
    <head>
        <title>Search for friend</title>
    </head>
    <body>
        <form action="searchPerson.php" method="get">
            Person: <input type="text" name="person" /><input type="submit" value="search" />
        </form>
    </body>
</html>

或直接运行

searchPerson.php?person=Rana

为什么你得到这样的消息是因为$person = $_GET['person'];从网址获取了人名，而你必须像searchPerson.php那样运行它，所以他们没有价值可供$ person检查。

- 编辑

查找代码以与不在列表中的人一起工作

需要帮助PHP作业 - 朋友匹配算法

2 个答案: