Question

我需要帮助在richTextBox中计算相同的单词，并且还想为它们分配数字/单词。一个盒子里有500,000个单词，所有单词只写3或6次。一种解决方案是写下我正在寻找的单词，在一个框中搜索并为其分配一个数字/单词。但是有太多的事情要做，如果有更快的方式它会帮助我很多。提前谢谢！

以下是我正在做的事情的代码，它并不代表我的要求。

        for (int i = 0; i < Url.Length; i++)
        {
            doc = web.Load(Url[i]);

            int x=0;
            int y=0;

            //here was a long list of whiles for *fors* down there, 
            //removed to be cleaner for you to see 
            //one example:                 
            //while (i == 0)
            //{
            //    x = 18;
            //    y = 19;
            //    break;
            //}

            for (int w = 0; w < x; w++)
            {
                string metascore = doc.DocumentNode.SelectNodes("//*[@class=\"trow8\"]")[w].InnerText;
                richTextBox1.AppendText("-----------");
                richTextBox1.AppendText(metascore);
                richTextBox1.AppendText("\r\n");
            }
            for (int z = 0; z < y; z++)
            {
                string metascore1 = doc.DocumentNode.SelectNodes("//*[@class=\"trow2\"]")[z].InnerText;
                richTextBox1.AppendText("-----------");
                richTextBox1.AppendText(metascore1);
                richTextBox1.AppendText("\r\n");
            }
        }

Answer 1

假设您有文本，从文件中读取，从某个网页下载或RTB ...使用LINQ将为您提供所需的一切。

string textToCount = "...";
// second step, split text by delimiters of your own
List<string> words = textToCount.Split(' ', ',', '!', '?', '.', ';', '\r', '\n') // split by whatever characters
            .Where(s => !string.IsNullOrWhiteSpace(s))                           // eliminate all whitespaces
            .Select(w => w.ToLower())                                            // transform to lower for easier comparison/count
            .ToList();
// use LINQ helper method to group words and project them into dictionary
// with word as a key and value as total number of word appearances
// this is the actual magic. With this in place, it's easy to get statistics.
var groupedWords = words.GroupBy(w => w)
   .ToDictionary(k => k.Key, v => v.Count());`

// to get various statistics
// total different words - count your dictionary entries
groupedWords.Count();
// the most often word - looking for the word having the max number in the list of values
groupedWords.First(kvp => kvp.Value == groupedWords.Values.Max()).Key
// mentioned this many times
groupedWords.Values.Max()
// similar for min, just replace call to Max() with call to Min()
// print out your dictionary to see for every word how often it's metnioned
foreach (var wordStats in groupedWords)
{
    Console.WriteLine($"{wordStats.Key} - {wordStats.Value}");
}

此解决方案与之前的帖子类似。主要区别在于此解决方案是使用单词分组，这很简单并将其放入字典中。到那里之后，很容易找到很多。

Answer 2

假设你有一个RichTextBox在某处运行，我们会称他为Bob：

        //Grab all the text from the RTF
        TextRange BobRange = new TextRange(
                // TextPointer to the start of content in the RichTextBox.
                Bob.Document.ContentStart,
                // TextPointer to the end of content in the RichTextBox.
                Bob.Document.ContentEnd
            );

        //Assume words are sperated by space, commas or periods, split on that and thorw the words in a List
        List<string> BobsWords = BobRange.Text.Split(new char[] { ' ', ',', '.' }, StringSplitOptions.RemoveEmptyEntries).ToList<string>();

        //Now use Linq for .net to grab what you want
        int CountOfTheWordThe = BobsWords.Where(w => w == "The").Count();

        //Now that we have the list of words we can create a MetaDictionary
        Dictionary<string, int> BobsWordsAndCounts = new Dictionary<string, int>();
        foreach( string word in BobsWords)
        {
            if (!BobsWordsAndCounts.Keys.Contains(word))
                BobsWordsAndCounts.Add( word, BobsWords.Where(w => w == word).Count(); )
        }

这就是你给一个单词分配一个数字的意思吗？您想知道RichTextBox中每个单词的计数吗？

或许添加一些上下文？

在richTextBox中搜索单词（windows窗体，c＃）

2 个答案: