Question

我正在使用laravel 5.5.13。

我App\Entity有App\Comment个App\Thumb个，public function show(Entity $entity) { return $entity->load('comments')->load('thumbs'); }个。{/ p>

现在我可以像这样轻松地获取评论和拇指：

{
    "id": 1,
    "kind": null,
    "name": "three",
    "created_at": "2017-11-01 04:29:22",
    "updated_at": "2017-11-01 04:29:22",
    "comments": [
        {
            "id": 5,
            "body": "no non o",
            "displayname_id": 4,
            "entity_id": 1,
            "created_at": "2017-11-01 05:16:14",
            "updated_at": "2017-11-01 05:16:14"
        }
    ],
    "thumbs": [
        {
            "id": 9,
            "like": 0,
            "displayname_id": 5,
            "entity_id": 1,
            "created_at": "2017-11-01 05:16:39",
            "updated_at": "2017-11-01 05:16:39"
        }
    ]
}

这提供了这样的数据：

$comment->displaynames()

但是，我还需要$thumb->displaynames()和App\Vote的列表，并且每个评论通过$comment->votes()都有很多{ // removed for concise (same as above) "comments": [ { // removed for concise (same as above) "votes": [ ..... // <<<<<<<<<<<<<<<<<<<<<<<<<<<<<< I want to get this ] }, { // removed for concise (same as above) "votes": [ ..... // <<<<<<<<<<<<<<<<<<<<<<<<<<<<<< I want to get this ] } ], "thumbs": [ { // removed for concise (same as above) } ], "displaynames": [ ..... // <<<<<<<<<<<<<<<<<<<<<<<<<<<<<< I want to get this ] }个。可能吗。我在枢轴上阅读了很多，但我真的很困惑。

我的目标是获得这样的数据：

displaynames

我们在这里看到每个votes中新的comment数组和{{1}}数组。

我是否必须在这里以一对多的关系使用数据透视？

Answer 1

你的控制器：

Entity::
with(['comments' => function($query){

    $query->with('votes');

}, 'thumbs' => function($query){

    $query->with('votes');

}])
->find($entity->id);

和关系：

entity has many comments
entity has many thumbs
thumb has many votes
comment has many votes

你应该告诉更多关于displayName关系的具体信息......

修改

Entity:: with(['comments' => function($query){ $query->with(['votes', 'displayName']); }, 'thumbs' => function($query){ $query->with(['votes', 'displayName']); }, 'displayName']) ->find($entity->id);

修改-2：

Entity:: with(['comments' => function($query){ $query->with(['votes' => function($query){ $query->with('displayName'); }, 'displayName']); }, 'thumbs' => function($query){ $query->with(['votes' => function($query){ $query->with('displayName'); }, 'displayName']); }, 'displayName']) ->find($entity->id);

通过关系获取相关数据

1 个答案: