我有比较两个表的问题： 甲
id x
1 2
1 5
1 4
1 6
乙
id x
1 2
1 5
1 4
1 6
我想知道表A和B中的数据是否与id = 1相同。
答案 0 :(得分：1)
这将列出id=1中a但b中没有SELECT a.*
FROM a
LEFT JOIN b ON a.id = b.id AND a.x = b.x AND a.id = 1
WHERE b.x IS NULL;
的所有b.x行：
id=1在左连接中，当{a.id，ax}对没有相应的{b.id，bx}对时，b将为空。< / p>
要列出a中SELECT b.*
FROM b
LEFT JOIN a ON b.id = a.id AND b.x = z.x AND b.id = 1
WHERE z.x IS NULL;
但不在a中的b行，只需转动查询：
b将两者合并以查找哪些行位于a但不是id=1，并且位于SELECT a.*, b.*
FROM a
LEFT JOIN b ON a.id = b.id AND a.x = b.x AND a.id = 1
WHERE b.x IS NULL
UNION SELECT a.*, b.*
FROM b
LEFT JOIN a ON b.id = a.id AND b.x = z.x AND b.id = 1
WHERE z.x IS NULL;
但不是$cordovaGeolocation.getCurrentPosition(options).then(
function(position){
$scope.startingLat = position.coords.latitude;
$scope.startingLng = position.coords.longitude;
services.projectStreets().then(function(result){
$scope.projects = result.data;
for (var i = 0; i < $scope.projects.length; i++) {
var endingLat = $scope.projects[i].position.lat;
var endingLng = $scope.projects[i].position.lng;
// this works to add key and value-> $scope.projects[i].distanceNew = "hi" + i;
services.googleMapsDistance($scope.startingLat, $scope.startingLng, endingLat, endingLng)
.then(function(distances){
$scope.distanceAway = distances.data;
$scope.projects[i]['distanceFrom'] = $scope.distanceAway.rows[0].elements[0].distance.text;
}
);
}
});
}
)
。如果查询未返回任何行，则<ion-item ng-repeat="project in projects" ng-click="goDeetz({{project.Nid}})">
<div class="row">
<div class="col-9">
{{project.title}}<br>
<a>{{project.project_dates}}</a>
</div>
<div class="col-3">
{{distanceAway.rows[0].elements[0].distance.text}}
</div>
</div>
</ion-item>
的两个表中的值都相同。如果它确实返回行，则它们是不同的行。
try:
br.form.find_control( 'Entries[registration_ip]').readonly = False
print "Form found ",
break
except mechanize.ControlNotFoundError:
print "ControlNotFoundError"
br.open(url)
br.select_form(nr = 0)
br.form.find_control( 'Entries[registration_ip]').readonly = False