我找到了generate n distinct colors的代码。我拿了代码并用它做了一个课
import colorsys
import itertools
from fractions import Fraction
class DistinctColorsGenerator:
def __init__(self):
self._bias = lambda x: (math.sqrt(x / 3) / Fraction(2, 3) + Fraction(1, 3)) / Fraction(6, 5)
self._gen_rgb = lambda x : colorsys.hsv_to_rgb(*x)
self._flatten = itertools.chain.from_iterable
self._hsvs = lambda: self._flatten(map(self._hsv, self._fracs()))
self._rgbs = lambda: map(self._gen_rgb, self._hsvs())
self._gen_colors = lambda: map(self._gen_color, self._rgbs())
def generate(self, number):
return list(itertools.islice(self._gen_colors(), number))
def _zenos_dichotomy(self):
for k in itertools.count():
yield Fraction(1, 2 ** k)
def _fracs(self):
yield 0
for k in self._zenos_dichotomy():
i = k.denominator
for j in range(1, i, 2):
yield Fraction(j, i)
def _hsv(self, h):
for s in [Fraction(6, 10)]:
for v in [Fraction(8, 10), Fraction(5, 10)]:
yield (h, s, v)
def _gen_color(self, x):
uint8tuple = map(lambda y: int(y * 255), x)
return list(uint8tuple)
我想将其转换为Kotlin,问题在于我的大部分Kotlin经验(以及Python)都在编写普通的无聊代码。而看起来这个通过生成无限序列并懒惰地评估它来解决问题。我可以看看Python代码,了解发生了什么,并编写一个简单而无聊的代码。但在此之前我想问一下是否有人可以展示如何在Kotlin中实现类似的东西
答案 0 :(得分:4)
我阅读了一些文档(正如评论中所建议的那样),这就是我提出的(以防万一有人会发现它有用)
class DistinctColorsGenerator {
fun generate(number: Int): List<ColorRgb> = generateRgbs.take(number).toList()
private val genHsvs = buildSequence {
fractions.forEach { createHsvColors(it).forEach { yield(it) } }
}
private val generateRgbs = buildSequence {
genHsvs.forEach { yield(it.toRgb()) }
}
private val zenosDichotomy = buildSequence {
var d = 1
while (true) {
yield(Fraction(1, d))
d *= 2
}
}
private val fractions = buildSequence {
yield(Fraction(0, 1))
zenosDichotomy.forEach {
val i = it.denominator.toInt()
for (j in 1 until i step 2) {
yield(Fraction(j, i))
}
}
}
private fun createHsvColors(h: Fraction<Int>) = buildSequence {
listOf(Fraction(6, 10)).forEach { s ->
listOf(Fraction(8, 10), Fraction(5, 10)).forEach { v ->
yield(ColorHsv(h, s, v))
}
}
}
}
类ColorRgb
,ColorHsv
,Fraction
只是数据类。 ColorHsv.toRgb()
我从here