Question

这是表格代码 - 当打印出来时，底部有一个空行。我不确定为什么要添加最后一行？这可能是if else声明吗？

first_name, last_name, house_number, street_name, city, state, zip_code, country

Answer 1

请尝试使用此代码：

<?php

$row = mysql_fetch_array($result);
$i = 0;
if ($row['Price'] == '0.00') {
    echo "<TABLE  width='100%'>\n";
    echo "<TR><TD id=tblrowsHead2>Item</TD><TD id=tblrowsHead2>Size</TD><TD id=tblrowsHead2>Contact</TD></TR>\n";
    do {
        if ($i % 2) { //this means if there is a remainder
            echo "<TR bgcolor=\"#E6E6FA\">\n";
        } else { //if there isn't a remainder we will do the else
            echo "<TR bgcolor=\"white\">\n";
        }
        echo '<TD id=Size>'.$row['Item'].'</TD><TD id=Size>'.$row['Size'].'</TD>';
        echo "<TD id=Price>Contact Us</TD></TR>\n";
        $i++;
    } while ($row = mysql_fetch_array($result)); //get a row from our result set
} else {
    do {
        if ($i % 2) { //this means if there is a remainder
            echo "<TR bgcolor=\"#E6E6FA\">\n";
        } else { //if there isn't a remainder we will do the else
            echo "<TR bgcolor=\"white\">\n";
        }
        echo '<TD id=Size>'.$row['Item'].'</TD><TD id=Size>'.$row['Size'].'</TD>';
        echo "<TD id=Price>$" . $row['Price'] . "</TD></TR>\n";
        $i++;
    } while ($row = mysql_fetch_array($result)); //get a row from our result set
}
//now let's close the table and be done with it
echo "</TABLE>\n";

当您在 for-loop 的第一行使用 mysql_fetch_array 时，您将丢失数据表的第一条记录，因此您将有一个空行最后

PHP Mysql - 添加一个空行无法弄明白

1 个答案: