Question

我正在尝试回复userID中存储的最后MySQL。但它没有显示。没有显示错误。

我试过了：

$stmti = $reg_user->runQuery("SELECT * FROM tbl_users");
    $rowi = $stmti->fetch(PDO::FETCH_ASSOC);
    $tf = $rowi['userID'];
echo $tf;

Answer 1

/ *注意：这仅适用于mysqli 更改参数＆＃34; host＆＃34;，＆＃34; username＆＃34;，＆＃34; password＆＃34;，＆＃34; db_name＆＃34;跟你的自己的 * /

$link = mysqli_connect("host","username","password","db_name");
$query = "  SELECT *
            FROM tbl_users";

$rows = array();
$result = mysqli_query($link, $query);
while($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) 
    $rows[] = $row;
$lastID = 0;
for ($i = 0 ; $i < count($rows) ; $i++)
     $lastID = $i;
echo $rows[$lastID]["userID"];

Answer 2

试试这个：

$sth = $reg_user->prepare("SELECT MAX(userID) as userID FROM tbl_users");
$sth->execute();
$result = $sth->fetch(PDO::FETCH_ASSOC);
$tf= ($result['userID']);
echo $tf;

显示来自MySQL的php中的最后一个userID

2 个答案: