Question

我的问题是关于JDBC SQL。我想要做的是使用员工实体中的用户名来检索我的登录密码。我有一个datainitalization单例bean来预先填充我的系统管理员。

GlassFish中的错误消息。

Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.6.1.v20150605-
31e8258): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: 
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 
'PASSWORD' in 'field list'
Error Code: 1054
Call: SELECT EMPLOYEEID, ACCESSRIGHT, ADDRESSLINE1, ADDRESSLINE2, 
CONTACTNUMBER, FIRSTNAME, LASTNAME, PASSWORD, POSTALCODE, USERNAME FROM 
EMPLOYEE WHERE USERNAME LIKE ?
bind => [1 parameter bound]
Query: ReadAllQuery(referenceClass=Employee sql="SELECT EMPLOYEEID, 
ACCESSRIGHT, ADDRESSLINE1, ADDRESSLINE2, CONTACTNUMBER, FIRSTNAME, LASTNAME, 
PASSWORD, POSTALCODE, USERNAME FROM EMPLOYEE WHERE USERNAME LIKE ?")

我使用用户名

检索登录密码的方法

    @Override
public Employee retrievePasswordByUsername(String username) throws UserNameNotFoundException
{
    //SELECT sl FROM SystemLogin sl WHERE sl.userName  = :inUserName
   return (Employee) em.createQuery("SELECT e FROM Employee e WHERE e.username LIKE :inUsername").setParameter("inUsername", username).getResultList();

}

这是我尝试登录方法。

@Override
public Employee employeeLogin(String username, String password) throws 
InvalidLoginCredentialException
{


    Employee employee = null;
    try {
        employee = retrievePasswordByUsername(username);
    } catch (UserNameNotFoundException ex) {
        Logger.getLogger(EmployeeController.class.getName()).log(Level.SEVERE, null, ex);
    }

     if(employee.getPassword().equals(password))
        {
            return employee;
        }
        else
        {
            throw new InvalidLoginCredentialException("Username does not exist or invalid password!");
        }
    }

最后，这是我为系统管理员提到的单例bean

     private void initializeData()
    {
        try {
            employeeControllerLocal.createNewEmployee(new Employee("Default", 
    "Administrator", "99999999", "NUS", "Computing","599999", 
    EmployeeAccessRight.ADMINISTRATOR, "admin", "password"));
        } catch (EmployeeExistException ex) {


 Logger.getLogger(DataInitializationSessionBean.class.getName()).log(Level.SEVERE
        , null, ex);
        } catch (GeneralException ex) {

  Logger.getLogger(DataInitializationSessionBean.class.getName()).log(Level.SEVERE, null, ex);
        }

    }

这是我员工实体类的一部分。

private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long employeeId;
@Column(length = 32, nullable = false)
private String firstName;
@Column(length = 32, nullable = false)
private String lastName;
@Column(length = 32, nullable = false)
private String contactNumber;
@Column(length = 32, nullable = false)
private String addressLine1;
@Column(length = 32, nullable = false)
private String addressLine2;
@Column(length = 32, nullable = false)
private String postalCode;
@Column(nullable = false)
@Enumerated(EnumType.STRING)
private EmployeeAccessRight accessRight;
@Column(unique = true)
private String username;
@Column(length = 32, nullable = false)
private String password;

感谢大家阅读本文！希望我能尽快找到解决方案。：）

PS：这个问题已经解决了。我还为任何需要检查是否需要保留任何保留字的人发布了一个链接： https://dev.mysql.com/doc/refman/5.7/en/keywords.html

Answer 1

由于PASSWORD是保留的工作，您需要在映射中明确指定转义的列名称

@Column(length = 32, nullable = false)
private String password;

应该改为

@Column(name = "`PASSWORD`", length = 32, nullable = false)
private String password;

或

@Column(name = "\"PASSWORD\"", length = 32, nullable = false)
private String password;

基于MySQL配置支持的变体（一些细节here）

在MySQL中转义保留字：未知列＆＃39;密码＆＃39;在＆＃39;字段列表＆＃39;

1 个答案: